The answer is 0,0719 mol.
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the following calculation to find the number of moles of Ar in 22g of Ar: 22g Ar X 1mol Ar/39.948g Ar = 0.55mol Ar
To find the number of molecules in 11.2 g of Ar, you need to use Avogadro's number and the molar mass of Ar. First, find the number of moles in 11.2 g using the molar mass of Ar (39.95 g/mol). Then, convert moles to molecules by multiplying by Avogadro's number (6.022 x 10^23 molecules/mol).
To find the number of moles, divide the given mass of argon by its molar mass. The molar mass of argon is approximately 39.95 g/mol. Number of moles of argon = 14.5 g / 39.95 g/mol Number of moles of argon = 0.362 moles
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.
.45mol of Mg3PO42
118g = 4.162oz
(6.02*10^24)*0.44 = 2.6488*10^24In 1 mol of any element there are 6.02*10^24 atoms.
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the following calculation to find the number of moles of Ar in 22g of Ar: 22g Ar X 1mol Ar/39.948g Ar = 0.55mol Ar
Mass = Moles x Ar = 12.5 x 24 = 300g
To find the number of molecules in 11.2 g of Ar, you need to use Avogadro's number and the molar mass of Ar. First, find the number of moles in 11.2 g using the molar mass of Ar (39.95 g/mol). Then, convert moles to molecules by multiplying by Avogadro's number (6.022 x 10^23 molecules/mol).
1 g of gold is equal to 0,006 moles.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
To find the number of moles, divide the given mass of argon by its molar mass. The molar mass of argon is approximately 39.95 g/mol. Number of moles of argon = 14.5 g / 39.95 g/mol Number of moles of argon = 0.362 moles
moles= mass/Mr so 525 divided by the Mr of ZnCl-2 Mr of ZnCl-2= (Ar of Zn= 65.37)+(2 x Ar of Cl= 2 x 35.5= 71) = 136.37 moles= 525/136.37 = 3.85 moles to 3 significant figures. (in grams) divide the answer by 1000 to get mg so 3.85/1000= 0.00385 moles
To find the number of moles in 0.476 grams of bromine, you first need to determine the molar mass of bromine, which is approximately 79.904 g/mol. Then, you can use the formula: moles = mass (g) / molar mass (g/mol). Therefore, in this case, 0.476 grams of bromine is equivalent to 0.006 moles.
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).