To find the number of molecules in 11.2 g of Ar, you need to use Avogadro's number and the molar mass of Ar. First, find the number of moles in 11.2 g using the molar mass of Ar (39.95 g/mol). Then, convert moles to molecules by multiplying by Avogadro's number (6.022 x 10^23 molecules/mol).
First we find the molar mass of citric acid (C6H8O7): (612.01 g/mol) + (81.01 g/mol) + (7*16 g/mol) = 192.13 g/mol Next, we calculate the number of moles in 192 g: 192 g / 192.13 g/mol ≈ 1 mol Finally, using Avogadro's number, we find the number of molecules in 1 mol: 1 mol * 6.022 x 10^23 molecules/mol = 6.022 x 10^23 molecules
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
The answer is 0,0719 mol.
To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.
The molar mass of acetic acid (C2H4O2) is 60 g/mol. Therefore, there are 1 mole of acetic acid molecules in 60 g. Based on Avogadro's number (6.022 x 10^23 molecules/mol), there are approximately 6.022 x 10^23 molecules in 60 g of acetic acid.
112g NO x 1 mol NO/30 g x 6.02x10^23 molecules/mole = 2.2z10^24 molecules
First we find the molar mass of citric acid (C6H8O7): (612.01 g/mol) + (81.01 g/mol) + (7*16 g/mol) = 192.13 g/mol Next, we calculate the number of moles in 192 g: 192 g / 192.13 g/mol ≈ 1 mol Finally, using Avogadro's number, we find the number of molecules in 1 mol: 1 mol * 6.022 x 10^23 molecules/mol = 6.022 x 10^23 molecules
22.0 g of silver chloride contain 0,918.10e23 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
1,4.10e23 molecules
The answer is 1,57.10e27 molecules.
2
0.34 kg = 340 gTo convert from kg to g, multiply by 1000.
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
0,34 g HCl contain 5,6.10e21 molecules.
The answer is 1,357.10 ex.23 molecules.