0,34 g HCl contain 5,6.10e21 molecules.
To calculate moles of HCl in 291.68 grams, use the molar mass of HCl which is 1 + 35.5 = 36.5g/mole. 291.68 g x 1 mol/36.5 g = 7.99 moles HCl (3 sig figs)
Clonidine is a drug that is used to treat attention deficit hyperactivity disorder (ADHD) and hypertension. Clonidine HCl is the hydrochloride salt of Clonidine (the free base), and it is more soluble in water than ins the free base. The 0.1 mg is the usual oral dose.
Without the specific details, one cannot be sure, but this is probably a back titration. You add a known amount of acid to your unknown, then titrate to measure how much has not reacted. You can then calculate how much of your first chemical must have been present.
They are in your saliva, when you eat saliva gets produced, and the enzymes are used to break down the food partially before it hits your stomach, then the stomach uses HCl with other enzymes to break the food down even more.AnswerHydrolytic enzymes (enzymes that break apart compounds) work by binding the substrate (the food in this case) to its active site. The enzyme will then break bonds in the substrate and make simpler molecules. This occurs many times with many enzymes.A correction on the first answer: enzymes in your saliva (salivary amylase) breaks down starch (carbs), but the digestion process for carbohydrates does not continue in the stomach -- only proteins are digested in the stomach because the HCl denatures the amylase.
First write the balanced chemical equation.HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l)Now convert 14.73mL into L by dividing by 1000.14.73 mL * (1L/1000mL) = 0.01473LMultiply the number of liters by the molar concentration of NaOH to get the number of moles in the amount of titrated solution.0.01473L * 0.1025 mol/L = 1.51*10^-3 mol NaOHThe endpoint of the reaction will be approximately the equivalence point, thus at the endpoint:mol HCl = mol NaOHThe coefficient of each reactant should match that of the balanced chemical equation. Both HCl and NaOH have a coefficient of 1 in the balanced chemical equation, thus it is a 1:1 exchange ratio.Now we know that we have reacted equal amounts of HCl and NaOH, so we also know the number of moles of HCl that were reacted in the equation: 1.51*10^-3 molIf we multiply the number of moles of HCl by the molar mass of HCl, we will get the number of grams of HCl present.1.51*10^-3 mol * 36.46 g/mol = 0.0551 g HClNow if we divide the number of grams of HCl present by the total mass of the original sample, we will get the percent by mass of hydrochloric acid in Lysol.0.0551g/0.5725g = 9.62% HCl
It depends on how many molecules of HCl you have. In one molecule of HCl there are 2 atoms present.
No, in pure liquid HCl, the molecules exist as HCl molecules and not as separate ions. It is only when HCl dissolves in water that it dissociates into its constituent ions (H+ and Cl-) due to the polar nature of water molecules.
To convert from number of molecules to moles, we use Avogadro's number: 1 mole = 6.022x10^23 molecules. Therefore, 1.0x10^19 HCl molecules is equal to 1.66x10^-5 moles of HCl.
HCl is a molecule which is made of two atoms - hydrogen and chlorine.
There are 6 hydrogen atoms and 6 chlorine atoms in 6 molecules of HCl. So, a total of 12 atoms.
Mass of HCL given=3.46kgs = 3460 grams of HCL No. of moles of HCL=Mass of HCL provided/Atomic mass of HCL=3460/36.5=94.8 moles no. of molecules=no. of moles x Avogadro number=94.8 x 6.022 x 1023 =57 x 1024 molecules.
They are molecules.
HCl is a polar covalent compound. When it is dissolved in Polar solvent H2O, it is ionized into its constituent ions H+ & Cl-. But when it is present gaseous form then it remains as Covalent compound HCl.
0.1mol
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
Molarity = moles of solute/liters of solution, so... 0.400M HCl (X mols HCl/0.250L ) = 0.100 moles HCl
c * V = 0.33 (mol/L) * 0.70 (L) = 0.231 = 0.23 mol HCl