The molar mass of acetic acid (C2H4O2) is 60 g/mol. Therefore, there are 1 mole of acetic acid molecules in 60 g. Based on Avogadro's number (6.022 x 10^23 molecules/mol), there are approximately 6.022 x 10^23 molecules in 60 g of acetic acid.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
Six molecules of glucose produce 12 molecules of acetic acid through the process of aerobic respiration.
Find the moles using the formula: moles= grams/molecular mass In this case, molecular mass = 24+4+32 = 60g/mol so 66/60 = 1.1 moles Then, using avogadro's constant, work out the number of molecules. n(molecules) = number of moles x 6.02x10^23 =1.1x 6.02x 10^23 =?
When the stopper is removed from a partly filled bottle containing solid and liquid acetic acid at 16.7 °C, a strong vinegar like odor is noticeable immediately. How many acetic acid phases must be present in the bottle? Explain.
The molar mass of acetic acid is 60,05 g.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
Six molecules of glucose produce 12 molecules of acetic acid through the process of aerobic respiration.
Find the moles using the formula: moles= grams/molecular mass In this case, molecular mass = 24+4+32 = 60g/mol so 66/60 = 1.1 moles Then, using avogadro's constant, work out the number of molecules. n(molecules) = number of moles x 6.02x10^23 =1.1x 6.02x 10^23 =?
Vinegar is a solution, not a pure substance and thus does not have "a molecule". This solution is composed (in typical household vinegar) of 92% to 95% water and 5% to 8% acetic acid with small amounts of other chemicals that provide flavor or color. Perhaps you intended to ask about the number of atoms in a molecule of acetic acid. The formula of acetic acid is C2H4O2 this gives 8 atoms in a molecule.
Vinegar is a mixture of water and acetic acid.
When the stopper is removed from a partly filled bottle containing solid and liquid acetic acid at 16.7 °C, a strong vinegar like odor is noticeable immediately. How many acetic acid phases must be present in the bottle? Explain.
The molar mass of acetic acid is 60,05 g.
According to the color and purpose, it may contain acetic acid, although many of them do not.
The volume of acetic acid would be 23.65 mL : 473 mL x 0.05 acetic acid/mL = 23.65 mL acetic acid
Both being two polar compounds, aniline is highly soluble in acetic acid.
One