2
100g sugar = 1619KJ of energy (according to Wikipedia)--> 1g sugar = 16.19KJ[1ATP]/[50KJ] * [16.19KJ]/[1 g sugar] = .3238[ATP]/[g sugar]-->3.08[g sugar]/[ATP]3.08[g sugar]/[ATP] * 38ATP = 117g sugar for 38 ATP
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules
3.345*10^23
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
1.24*10^22
Consuming 1g of fat yields about 9 kcal/g and can produce around 38 ATP molecules. Consuming 1g of carbohydrate provides about 4 kcal/g and can produce around 36-38 ATP molecules. So, in this case, consuming 1g of fat would yield slightly more ATP compared to 1g of carbohydrate.
Assuming a density of 1.0 g/ml for water, then 10 ml H2O = 10 g10 g H2O x 1 mol/18 g = 0.5555 moles H2O0.5555 moles x 6.02x10^23 molecules/mole = 3.34x10^23 molecules of H2O in 10 ml
In aerobic respiration, 36 or 38 molecules of ATP per molecule of glucose, depending on how many are gained through the electron transfer system. In anaerobic respiration 2 molecules of ATP per molecule of glucose, though higher yields can occur in higher temperatures (as much as 9 ATP molecules per molecule of glucose)
The molar mass of acetic acid (C2H4O2) is 60 g/mol. Therefore, there are 1 mole of acetic acid molecules in 60 g. Based on Avogadro's number (6.022 x 10^23 molecules/mol), there are approximately 6.022 x 10^23 molecules in 60 g of acetic acid.
Divide ten by Molecular mass.Then multiply by 6.022 × 10^23
To determine the number of molecules in a 4.30 g sample of dimethylmercury (MM = 230.64 g/mol), you need to first calculate the number of moles using the formula: moles = mass / molar mass. Then, you can convert moles to molecules using Avogadro's number (6.022 x 10^23 molecules/mol). So, for dimethylmercury: moles = 4.30 g / 230.64 g/mol, then molecules = moles x 6.022 x 10^23.
To find the number of molecules in 54.3 g of water (H2O), you first need to convert the mass of water to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 54.3 g / 18.015 g/mol = 3.013 moles, then, 3.013 moles * 6.022 x 10^23 molecules/mol = 1.816 x 10^24 molecules of H2O in 54.3 g of water.