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How many grams of sugar are needed for 38 ATP?

100g sugar = 1619KJ of energy (according to Wikipedia)--> 1g sugar = 16.19KJ[1ATP]/[50KJ] * [16.19KJ]/[1 g sugar] = .3238[ATP]/[g sugar]-->3.08[g sugar]/[ATP]3.08[g sugar]/[ATP] * 38ATP = 117g sugar for 38 ATP


How many molecules of S8 would be necessary to obtain 1.000 g of S?

(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules


How many molecules in 1 g of water?

3.345*10^23


How many molecules of H2O are there in 1.0 g of H2O?

There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.


How many molecules are contained in a g sample of dimethylmercury?

1.24*10^22


If you consume 1 g of each what which will yield the most ATP?

Consuming 1g of fat yields about 9 kcal/g and can produce around 38 ATP molecules. Consuming 1g of carbohydrate provides about 4 kcal/g and can produce around 36-38 ATP molecules. So, in this case, consuming 1g of fat would yield slightly more ATP compared to 1g of carbohydrate.


How many molecules of water is present in 10 ml of water?

Assuming a density of 1.0 g/ml for water, then 10 ml H2O = 10 g10 g H2O x 1 mol/18 g = 0.5555 moles H2O0.5555 moles x 6.02x10^23 molecules/mole = 3.34x10^23 molecules of H2O in 10 ml


How many atp's are produced from 1 molecule of glucose?

In aerobic respiration, 36 or 38 molecules of ATP per molecule of glucose, depending on how many are gained through the electron transfer system. In anaerobic respiration 2 molecules of ATP per molecule of glucose, though higher yields can occur in higher temperatures (as much as 9 ATP molecules per molecule of glucose)


How many molecules are there in 60 g of acetic acid C2H4O2?

The molar mass of acetic acid (C2H4O2) is 60 g/mol. Therefore, there are 1 mole of acetic acid molecules in 60 g. Based on Avogadro's number (6.022 x 10^23 molecules/mol), there are approximately 6.022 x 10^23 molecules in 60 g of acetic acid.


How many molecules are in 10 g of ch4?

Divide ten by Molecular mass.Then multiply by 6.022 × 10^23


How many molecules are contained in a 4.30 g sample of dimethylmercury?

To determine the number of molecules in a 4.30 g sample of dimethylmercury (MM = 230.64 g/mol), you need to first calculate the number of moles using the formula: moles = mass / molar mass. Then, you can convert moles to molecules using Avogadro's number (6.022 x 10^23 molecules/mol). So, for dimethylmercury: moles = 4.30 g / 230.64 g/mol, then molecules = moles x 6.022 x 10^23.


How many molecules of H2O are in 54.3 g H2O?

To find the number of molecules in 54.3 g of water (H2O), you first need to convert the mass of water to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 54.3 g / 18.015 g/mol = 3.013 moles, then, 3.013 moles * 6.022 x 10^23 molecules/mol = 1.816 x 10^24 molecules of H2O in 54.3 g of water.