6.022
3 moles of Zn is equal to 18.09x1023 atoms. I used Avogadro's Number : 6.03x1023 particles/mol This number is the number of atoms or molecules in a mol of any substance. 3 moles X 6.03x1023 particles/mol = 18.09x1023 atoms
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
To calculate the number of iron atoms in 0.0178 mol of iron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Number of iron atoms = 0.0178 mol x 6.022 x 10^23 atoms/mol = 1.07 x 10^22 atoms.
To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). For 1.33 x 10^24 Zn atoms, we have: 1.33 x 10^24 Zn atoms / 6.022 x 10^23 atoms/mol ≈ 2.21 moles of Zn atoms.
3 moles of Zn is equal to 18.09x1023 atoms. I used Avogadro's Number : 6.03x1023 particles/mol This number is the number of atoms or molecules in a mol of any substance. 3 moles X 6.03x1023 particles/mol = 18.09x1023 atoms
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
To calculate the grams of zinc containing 6x10^23 atoms, we need to determine the molar mass of zinc, which is approximately 65.38 g/mol. Then, we can use Avogadro's number to find the number of moles (n) of zinc atoms: n = (6x10^23 atoms) / (6.022x10^23 atoms/mol). Finally, we can calculate the mass of zinc: mass = n x molar mass.
Molar mass of Zinc = 65.4 g mol-1 No. of moles of 20.0 g of Zinc = 20.0 / 65.4 = 0.305810397 mol No. of atoms = 0.305810397 L (where L is the Avogadro constant) = 1.8416 x 1023
To find the number of moles of zinc, divide the sample's weight by the atomic weight of zinc (65.38 g/mol). This gives approximately 0.534 moles of zinc. To find the number of atoms, multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) to get around 3.21 x 10^23 atoms in the sample.
To find the number of atoms in 12g of zinc, you would first determine the molar mass of zinc (65.38 g/mol), then calculate the number of moles in 12g (12g / 65.38 g/mol). Finally, you would convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.
To calculate the number of atoms in 100g of zinc, you first need to determine the molar mass of zinc, which is approximately 65.38 g/mol. Next, divide the given mass by the molar mass to find the number of moles of zinc. Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
6.8/65.38=0.104mol 0.104 x 6.022 x 10^23=6.263^10 x22
From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
If zinc reacts with excess copper(ll) sulfate, a 1:1 molar ratio will be maintained. Therefore, 5.8 mol of zinc will produce 5.8 mol of copper.