1000 ppm = 1000 mg/ l
1N NaCl = 58.5 gm/l
ok 1000 mg/l = 1 gm/l
= 0.1gm/100 ml
= 0.1 % wt.
on the other hand 1 % wt. = 10,000 ppm
so , 0.1 %wt. = 1000 ppm
so you need to put 0.1 gm in 100 ml = 1 gm in 1000 ml to get 1000 ppm
~58.5 g ~58.5 g 58.443 g
0,2 g sodium chloride
0.45
29
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
2.27
1 mmol sodium = 23 mg sodium chloride 80 mmol sodium chloride = 80 x 23= 1840 mg sodium chloride
234 grams
Ammonium Nitrate! Fo sho doe.
4 milliequivalents of sodium chloride solution is a solution having 0,2338 g in 1 L.
You get salt at the bottom of the pan!
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
The sodium chloride mass needed is 292,2 g
The mass is 234,8 g.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
That depends on how much solvent you are dissolving the 9 grams of salt in.
The needed mass of sodium chloride is 29,22 g.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
2.27
0.0554 M
The mass of sodium hypochlorite in 2,5 kg solution is 131,25 g.Sodium chloride is only the product of a decomposition.