I assume you mean this reaction.
2Mg + O2 --> 2MgO
16 or 160 ???
Either way the form is the same. We will use the 16 grams.
16 g O2 (1 mole O2/32 grams)(2 mole Mg/1 mole O2)
= 1.0 mole magnesium needed
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How many moles of magnesium are needed to react with 16 g of molecular oxygen?
so close to one that it doesn't matter about the variation.
0.50 moles O2 in 16 g (2 significants)
16g oxygen is 0.5mol, because oxygen is naturally O2 with a molar mass of 32g/mol. Total molecules is 0.5 x Avogardo, which is about 3x10^23 O2 molecules.
16g/32g=.5 mol
16 g oxygen is equal to 0,5 mole
0,5 moles
24
24 grams
16.0 g
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
246 grams is approx 1.23 moles of Hg(II) therefore the ratio is 1:1 so you need 1.23 moles of S which is approx 39.5 grams
2.8g
Two magnesium atoms.
16.0 g
A lot
50
47.6 grams
cannot answer without more info.
I can't
uykfruykyuyk
63 g of water are needed.
0,257 g hydrogen are needed.
13.8 g
When you resubmit your question please indicate which gas is of interest to you.