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The molecular weight of ethane (C2H6) is 30.07 so 65.7 g of it would be 2.185 moles. Each mole of ethane burned would yield 2 moles of carbon dioxide - which has a molecular weight of 44.01.

You would get

2 x 2.185 x 44.01 = 96.2 g of carbon dioxide

Note that the statement of burning with excess oxygen is important because it would push the reaction more to completion and limit the formation of carbon monoxide to an insignificant amount.

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7y ago
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3y ago
shyt wrong fam
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Anonymous

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3y ago
bullshyt
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9y ago

C2H202 refers to multiple chemicals of the same molecular formula. That being said the molecule has a weight of 58.04 grams per mole. For every 1 mole of C2H2O2 we have 2 moles of oxygen (O), a ratio of 1:2. In this problem we are given a quantity of 65 grams, or 1.1 moles of C2H2O2. Therefore, this also gives us 2.2 moles of O through the molar ratio. 2.2 moles of O thus equals 35 grams. (O has weight of 16.00 grams per mole).

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13y ago

2x12+2x1+2x16=58

32(o2)/58(total amu)= .55

.55x65(# of grams of substacnce)=35 g of o

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15y ago

If your question is " how many moles of oxygen are in 65.06 grams?" we should consider the gas O2 which has an atom/mol weight of 16 grams: 65.06/16= 4.06625 moles

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9y ago

C2H2O2 has a molar mass of 58.0361 grams per mol. There are then 1.12 moles of glyoxal. There is then 1.12 moles of O2 as well, which equates to 35.838 grams.

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11y ago
8.76g of O2
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9y ago

You need 215,2 g oxygen.

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10y ago

31

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3y ago

the answer is 192g

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31

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Q: How many grams of oxygen are in 56 g of c2h2o2?
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How many grams of iron must be added to 16 grams of oxygen to equal 44 grams of iron 3 oxide?

30.8g of iron (approximately) reacted with 13.2g of oxygen will yield 44g of iron(III) oxide (Fe2O3) with 2.8g of oxygen left unreacted. This assumes atomic mass numbers of 56 and 16 respectively for iron and oxygen. The actual mass number of iron is 55.847 and oxygen 15.9994 making the figures 30.775g of iron and 13.225g of oxygen with 2.775g of unreacted oxygen. Of course this is an exothermic reaction so will there be a tiny tiny loss of mass in the system as it is converted to heat energy, according to E=MC^2? I'll let you work that one out...


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