The molecular weight of ethane (C2H6) is 30.07 so 65.7 g of it would be 2.185 moles. Each mole of ethane burned would yield 2 moles of carbon dioxide - which has a molecular weight of 44.01.
You would get
2 x 2.185 x 44.01 = 96.2 g of carbon dioxide
Note that the statement of burning with excess oxygen is important because it would push the reaction more to completion and limit the formation of carbon monoxide to an insignificant amount.
C2H202 refers to multiple chemicals of the same molecular formula. That being said the molecule has a weight of 58.04 grams per mole. For every 1 mole of C2H2O2 we have 2 moles of oxygen (O), a ratio of 1:2. In this problem we are given a quantity of 65 grams, or 1.1 moles of C2H2O2. Therefore, this also gives us 2.2 moles of O through the molar ratio. 2.2 moles of O thus equals 35 grams. (O has weight of 16.00 grams per mole).
2x12+2x1+2x16=58
32(o2)/58(total amu)= .55
.55x65(# of grams of substacnce)=35 g of o
If your question is " how many moles of oxygen are in 65.06 grams?" we should consider the gas O2 which has an atom/mol weight of 16 grams: 65.06/16= 4.06625 moles
C2H2O2 has a molar mass of 58.0361 grams per mol. There are then 1.12 moles of glyoxal. There is then 1.12 moles of O2 as well, which equates to 35.838 grams.
You need 215,2 g oxygen.
31
the answer is 192g
31
30.8g of iron (approximately) reacted with 13.2g of oxygen will yield 44g of iron(III) oxide (Fe2O3) with 2.8g of oxygen left unreacted. This assumes atomic mass numbers of 56 and 16 respectively for iron and oxygen. The actual mass number of iron is 55.847 and oxygen 15.9994 making the figures 30.775g of iron and 13.225g of oxygen with 2.775g of unreacted oxygen. Of course this is an exothermic reaction so will there be a tiny tiny loss of mass in the system as it is converted to heat energy, according to E=MC^2? I'll let you work that one out...
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
56
Barium has 56 eletrons56 electrons and protons.
The equation for this reaction is 3 Ca + N2 -> Ca3N2. The gram molecular mass of Ca3N2 is 148.25, and the gram atomic mass of Ca is 40.08. Therefore, the amount of Ca3N2 that could theoretically be formed from 56 grams of calcium is 56(148.25)/(3 X 40.08) or 69.10 grams. The percentage yield is therefore 100(32)/(69.10) or 46 %, to the justified number of significant digits.
56 hectograms = 5600 grams
1 kilogram = 1,000 grams 2 kilograms = 2,000 grams 56 kilograms = 56,000 grams
56 grams 448 grams in a pound / 8 = 56 grams
2 ounces = 56.7 grams.
On Earth the force F = 1 newton is the mass m = 102 grams. 56 grams are 0.55 newtons.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
56oz = 1588g
56000
7
56 kg = 56 000 g
Kilo is the prefix for 1000. So 1 kilogram is 1000 grams. So 5.6 kilograms is 5600 grams.5,600g
Approximately 56 grams of sugar in 1/4 cup.