The chemical formula for Calcium Oxide is CaO.
The Atomic weigth of Calcium is 40.078.
The Atomic weight of Oxygen is 15.999
The Molecular weight of CaO is therefore 56.077
Thus 100g of CaO would contain (15.999/56.077)*100 = 28.53041353852738 grams of Oxygen and (40.078/56.077)*100 = 71.46958646147262 grams of Calcium.
There are 40.08 grams of calcium in 100 grams of CaCO3. To find the amount of calcium in 418 grams of CaCO3, you can set up a proportion and calculate that there are approximately 167.2 grams of calcium in 418 grams of CaCO3.
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
To calculate the amount of calcium oxide needed to produce 36.0 g of mercury (Hg), we need to first determine the molar ratio between calcium oxide and mercury. The molar ratio can be determined from the balanced chemical equation of the reaction. Once the molar ratio is known, we can use it to find the amount of calcium oxide needed to produce 36.0 g of mercury.
Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
800 g oxygen are needed.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
The balanced chemical equation for the reaction is: 2Ca + O2 --> 2CaO This equation shows that for every 2 moles of calcium that react with 1 mole of oxygen, 2 moles of calcium oxide are formed. Since the molar mass of Ca is 40 g/mol, and the molar mass of CaO is 56 g/mol, the 10 grams of calcium would react with 7 grams of oxygen to form 14 grams of calcium oxide.
There are 40.08 grams of calcium in 100 grams of CaCO3. To find the amount of calcium in 418 grams of CaCO3, you can set up a proportion and calculate that there are approximately 167.2 grams of calcium in 418 grams of CaCO3.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
For every 40 grams of calcium (Ca), 32 grams of oxygen (O) will be needed to react. This is based on the chemical formula for calcium oxide (CaO), where one calcium atom reacts with one oxygen atom to form one molecule of CaO.
Lithium chloride is not transformed in calcium chloride.
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
To burn 1 mole of acetylene (C2H2), 3 moles of oxygen (O2) are required. The molar mass of acetylene is 26.04 g/mol and of oxygen is 32.00 g/mol. First, convert 13.50g acetylene to moles, calculate the moles of oxygen required, and then convert back to grams to find the mass of oxygen needed.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.