You would basically start off by multipying the 2.5X0.2 because you must change the mL to L and by doing so you will get : 0.5
once you have the 0.5 you then must find the molar mass # of potassium carbonate and to do so you must look at a table of elements. The molar mass number of K2CO3
is: 39(2)+12+16(3) = 138
Now that you have the molar mass # which is 138 you must multiply it by 0.5 from before
so lastly you: 138X0.5= 69g
And that's how you do it... :)
increase The coefficient :3.25x10-7 The expansion of each dimension is: 32.5 x10-7 x 100 = 32.5 x10-5 Each dimension increases by this amount, so volume increases by 32.5 x10-5 cubed, which is 34 E-12 so the volume will increase by 200ml x 34 E-12 = 6,800 E-12 ml
20.0 g = 20.0 (g) / 40.0 (g/mol) = 0.500 mol200 mL = 200 (mL) / 1000 (mL/L) = 0.200 LFinally:molarity = 0.500 (mol) / 0.200 (L) = 2.50 mol/L
To find this answer it is necessary to first find the chemical formula of aluminum sulfate utilizing the valence charges from the periodic table. Aluminum Sulfate is a molecular formed by the ionic bonding of aluminum to to the polyatomic ion of sulfate Al = +3 SO4 is a polyatomic ion with a charge of -2 Therefore after balancing the equation, you get the chemical formula Al2(SO4)3 Next, in order to find osmolarity, you must first find molarity. This is done by converting grams to moles. Moles are calculated in grams/Liter and is equal to the molecular weight. What is the molecular weight of aluminum sulfate. Looking at the periodic table, you sum the atomic weights of each element, shown in AMUs. Al = 27 (x2) = 54 S = 32 (x3) =96 O = 16 (x12) = 192 We add these up to determine the molecular weight of the substance, which can be used to determine the molarity of this solution. MW = 342g, which means that one mole of aluminum sulfate is 342 grams per liter of water. We can now use the information presented in the above problem to determine molarity 10 grams dissolved in 200 ml of water. Since measurements are in grams per liter, we can assume that if 10 grams were dissolved in 200 ml of water, then 50 grams will dissolve in 1000 ml, or 50 grams per liter (multiply both factors by five). We must use our grams of solute to convert grams into our molarity 50 g x 1 mole/342 grams of aluminum sulfate to determine the molarity. = .15 M At this point, to determine osmolarity, you must be aware that osmolarity is the measure of PARTICLES within a solution per liter. Realizing that aluminum sulfate is held together by an ionic bond, it will freely dissolve in water and produce Al ions and SO4 ions. So we sum the particles of each: 2 Al ions per molecule 3 SO4 ions per molecule Therefore, multiplying the molarity of the aluminum sulfate solution times 5 (total 5 particles from each molecule) will give you the osmolarity. = 0.73 Osm per liter of aqueous solution.
200ml of solution x 20% of alcohol = 40ml of alcohol..
Each 200ml contains- 1) Sodium Chloride= 250mg 2) Potassium Chloride= 30 mg 3) Sodium Citrate = 580 mg Calculate osmolarity of Sodium, Poatassium and Chloride
40mn
a lot
Density of etyl acetate
1200
237.5 mL (200mL if you are keeping track of significant figures). Molarity is moles/liters. To make 900mL of a 2M solution, you need 1.8 moles of solute. There are 1.8 moles of solute in 237.5 mL of 8M solution.
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
200mL equates to 2dL (deciliters).
X/200 * 100 = 2.5 x= 5g
Change 200mL into decimal.