8.30 moles (NH4)2S (8 moles H/1 mole (NH4)2S)(6.022 X 1023/1 mole H)
= 3.99 X 1025 atoms of hydrogen
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The formula for ammonium carbonate is (NH4)2CO3. In one mole of ammonium carbonate, there will be two moles of nitrogen, eight moles of hydrogen, one mole of carbon, and three moles of oxygen. There are 6.02x1023 atoms per mole. So, for one mole of ammonium carbonate there are: 2 mol N * 6.02x1023 atoms per mole = 1.20x1024 atoms of nitrogen 8 mol H * 6.02x1023 atoms per mole = 4.82x1024 atoms of hydrogen 1 mol C * 6.02x1023 atoms per mole = 6.02x1023 atoms of carbon 3 mol O * 6.02x1023 atoms per mole = 1.81x1024 atoms of oxygen
8,941 moles o ammonium sulphide - (NH4)2S - contain 250,4678 g of nitrogen or 41,11 % nitrogen.
1 molecule of hydrogen contains 2 hydrogen atoms,so 1 mole of hydrogen consists of 2 moles of atoms.
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide
The answer is 1,72.10e25 atoms.
4,2.10e25 H atoms
8.70 moles (NH4)2S x 6.02x10^23 molecules/mole x 8 H atoms/molecule = 4.18x10^25 H atoms
(NH4)2S 4.10 moles (NH4)2S (8 moles H/1 mole (NH4)2S)(6.022 X 10^23/1 mole H) = 1.98 X 10^25 atoms of hydrogen
Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.
It is important to know that the percent of nitrogen in 4.444 moles of ammonium sulfide is the same as the percent of nitrogen in 454 grams or 4843 moles or 96 kg, etc. Remember the law of definite proportions - chemical compounds always contain the same proportion of elements by mass. Perhaps you were asking how much nitrogen is in 4.444 moles of ammonium sulfide given the percent of nitrogen in any given mass. So we'll do that too: find the percent of nitrogen in any given sample and apply it specifically to 4.444 moles.Before we go directly to the 4.444 moles, we have to figure out how much nitrogen is in any amount of ammonium sulfide by percent. To do this, we need the atomic weights of the elements and add them up to find the total molar mass of the compound.Ammonium sulfide = (NH4)2SNitrogen = 14.0 grams × 2 = 28.0 gramsHydrogen = 1.01 grams × 8 = 8.08 gramsSulfur = 32.1 grams------------------------------------------------------Ammonium sulfide = 68.2 gramsNow we take the mass of nitrogen and divide it by the total mass to get our percent.Nitrogen ÷ Ammonium sulfide = % Nitrogen28.0 grams ÷ 68.2 grams = 0.411 = 41.1% Nitrogen in Ammonium sulfideSince we know that in any amount of Ammonium sulfide contains 41.1% of Nitrogen, we can apply it to the mass given.41.1% of 4.444 moles = .411 × 4.444 = 1.83 moles of Nitrogen in 4.444 moles Ammonium sulfide
The formula for ammonium carbonate is (NH4)2CO3. In one mole of ammonium carbonate, there will be two moles of nitrogen, eight moles of hydrogen, one mole of carbon, and three moles of oxygen. There are 6.02x1023 atoms per mole. So, for one mole of ammonium carbonate there are: 2 mol N * 6.02x1023 atoms per mole = 1.20x1024 atoms of nitrogen 8 mol H * 6.02x1023 atoms per mole = 4.82x1024 atoms of hydrogen 1 mol C * 6.02x1023 atoms per mole = 6.02x1023 atoms of carbon 3 mol O * 6.02x1023 atoms per mole = 1.81x1024 atoms of oxygen
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
The number of moles is 18.56.
Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.
Ammonium chloride has the formula of NH4Cl. Thus, in each mole there are 4 moles H, 1 mole N and 1 mole Cl for a total of 6 moles of atoms. Then 6.02x10^23 atoms/mole x 6 moles = 3.6x10^24 atoms.