N2+3H2--> 2NH3 answer 3 moles of H2 bonds are broken
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
The helium and liquid hydrogen won't mix. The liquid nitrogen is not cold enough to cause the helium to liquify, and the helium is an inert gas and will not react with the nitrogen.
The reaction is: 2 H2O2 -------------2 H2O + O2 The hydrogen peroxide is the reactant; water and oxygen are the products.
Hydrogen peroxide (H2O2) spontaneously degrades to water and oxygen according to the reaction: 2H2O2 ---> 2H2O + O2 As with any reaction, higher temperature increases the rate of the reaction. Specifically, higher temperature will accelerate the rate that H2O2 degrades.
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nitrogen
a reaction with nitrogen and hydrogen
nitrogen gas and hydrogen gas
Nitrogen and hydrogen react to form ammonia. This is the reaction in the Haber process, in which the gases are mixed at high pressure and moderately high temperature and passed over an iron catalyst.
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Nitrogen has four bonds with hydrogen.
Studies on the subject have continually proven that there is no such thing as a phsical reaction.
Haber's process
After this reaction ammonia (NH3) is obtained.
Of course; 3 H2 + N2 -------2 NH3
The equation for the reaction is N2 + 3 H2 -> 2 NH3. The gram atomic mass of nitrogen is 14.0067, and the gram atomic mass of hydrogen is 1.00794. Therefore, the mass fraction of nitrogen in ammonia is 14.0067/[14.0067 + (3*)(1.00794)] or about 0.8225, and, since nitrogen and hydrogen are the only two elements present, the mass fraction of hydrogen is 1*- 0.8225 or about 0.1775. The mass fraction of nitrogen in the amounts of nitrogen and hydrogen specified is 44.5/(44.5 + 2.58) or about 0.945. Therefore, hydrogen is the limiting reactant in this mixture, and the mass of ammonia produced is 2.58/0.1775 or 14.5 grams, to the justified number of significant digits. ________________ *An exact integer.
3h2 + n2 = 2nh3