It does not. It needs 3 Hydrogen molecules and 1 nitrogen molecule to produce 2 moles of ammonia. Also it needs a very high pressure and a temperature of around 200 C and usually a catalyst too. Then ammonia can be formed. It is known as the Haber process.
N2 + 3H2 <-----> 2NH3
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∙ 12y agoWiki User
∙ 14y agothis reaction is not possible.
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
H2 n2
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
2 mol H2 x 2 mol H2O/2 mol H2 x 18 g H2O/1 mol H2O = 36 g H2O
The reaction for the Haber process isN2 + 3 H2 ⇌ 2 NH3Amount of N2 = 3.41/28.0 = 0.122molAmount of H2 = 2.79/2.0 = 1.40molAccording to the stoichiometry of the reaction, 1 mol of N2 reacts with 3 mol of H2. 0.122mol of N2 will therefore react with only 0.366mol of H2, but there is 1.40mol of H2 available. Thus H2 is in excess and N2 is the limiting reactant.1mol of N2 reacts to form 2 mol of NH3.Under the maximum possible yield, 0.122mol of N2 reacts to form 0.244mol of NH3.Mass of NH3 = 0.244 x 17.0 = 4.15g
N2 + 3 h2 --> 2 nh3
Ammonia
(N2) + 3(H2) = 2(NH3)
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
This is a synthesis reaction.
16,45 g nitrogen are needed.
H2 n2
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
No, it's not balanced because the number of hydrogens and nitrogens on the left is not equal to the number on the right. 3H2 + N2 --> 2NH3
You need the balanced chemical equation for N2 and H2 combining to form ammonia, NH3.N2 (g) + 3 H2 (g) -----> 2 NH3 (g)Moles NH3 = ( 55.5 g NH3 ) / ( 17.03 g/mol NH3 ) = 3.259 moles of NH3n N2 required = ( 3.259 mol NH3 ) ( 1 N2 mol / 2 NH3 mol ) = 1.629 moles N2m N2 required = ( 1.629 mol N2 ) ( 28.103 g N2 / mol N2 ) = 45.67 g N2 needed
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