Put a 2 to NH3 first.Then a 3 to Hydrogen.
True, the balanced equation N2 + 3H2 -> 2NH3 shows that 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3. From the molar masses of N2 (28g/mol), H2 (2g/mol), and NH3 (17g/mol), it can be calculated that 1g of N2 reacts with 3g of H2 to form 2g of NH3.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
16,45 g nitrogen are needed.
The reactants are hydrogen and nitrogen.
8 mol
(N2) + 3(H2) = 2(NH3)
True, the balanced equation N2 + 3H2 -> 2NH3 shows that 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3. From the molar masses of N2 (28g/mol), H2 (2g/mol), and NH3 (17g/mol), it can be calculated that 1g of N2 reacts with 3g of H2 to form 2g of NH3.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
16,45 g nitrogen are needed.
This is a synthesis reaction.
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
The reactants are hydrogen and nitrogen.
1/2 n2 + 3/2 h2 = nh3 sorry about the lower case they wouldn't let me summit it with caps N2 + 3 H2 => 2 NH3
The reaction of 2 liters of N2 and 2 liters of H2 to form NH3 is based on the balanced equation: N2 + 3H2 -> 2NH3. Since 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3, 2 liters of N2 and 2 liters of H2 would produce 2 liters of NH3 following the stoichiometry of the balanced equation.
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
The expression n2 + h2 + nh3 is the sum of the squares of two numbers n^2 and h^2, along with the product of n and h multiplied by 3.