2NaN3 --> 2Na + 3N2
2.88 mol of NaN3 reacted * (3 mol of N2 produced / 2 mol of NaN3 reacted) =
4.32 mol of N2
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
Answer: 8 mol NO First, you start by writing the decomposition of N2O2CL2: N2O2Cl2=> 2NO +Cl2 (in reality, we should expect NO2 or N2 and O2 to be products in place of NO, but we'll assume the problem given expects this decomposition) Then, using stochiometry: 4 mol N2O2Cl2 * 2 mol NO/1 mol N2O2Cl2= 8 mol NO
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
0,75 moles of nitrogen
To calculate the total number of moles of sodium azide in a 52-g sample, you need to divide the mass of the sample by the molar mass of sodium azide (65.01 g/mol). So, 52 g / 65.01 g/mol = 0.799 moles of sodium azide.
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
Sodium reacts with water. 0.652 NaOH moles will form.
0,028 moles carbonic are obtained.
You have answered the question for yourself. 4 Na + O2 = 2Na2O The molar ratios are 4:1 :: 2 The answer is '2'.
The number of atoms is 45,166.10e23.
The balanced chemical equation for the decomposition of sodium carbonate is: 2Na2CO3 -> 2Na2O + 3CO2. Therefore, to find the mass of water produced, we need to calculate the molar mass of Na2O and CO2 and then convert the given mass of Na2CO3 to moles. From there, we can use the mole ratio from the balanced equation to determine the mass of water produced.
Answer: 8 mol NO First, you start by writing the decomposition of N2O2CL2: N2O2Cl2=> 2NO +Cl2 (in reality, we should expect NO2 or N2 and O2 to be products in place of NO, but we'll assume the problem given expects this decomposition) Then, using stochiometry: 4 mol N2O2Cl2 * 2 mol NO/1 mol N2O2Cl2= 8 mol NO
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.