0
The equation for the formation of carbon dioxide from carbon and oxygen is C + O2 -> CO2 . Therefore, one mole of carbon dioxide can be formed from each mole of diatomic oxygen. To the justified number of significant digits, the gram molecular mass of diatomic oxygen is 32. Therefore 54/32 or 1.69 moles of carbon dioxide can be produced. (The last digit is smaller than the others to show that it may not be accurate within 1 digit.)
What else can I help you with?
How many moles of carbon are there from the original sample of 11.0 grams of carbon dioxide and 4.50 grams of water with a combustion of 7.50 grams?
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
How many grams of carbon dioxide are produced when 23.5 g of 1-heptanol react with excess oxygen in a combustion reaction?
To find the grams of carbon dioxide produced, first determine the moles of 1-heptanol using its molar mass. Then, use the balanced combustion equation of 1-heptanol to find the moles of CO2 produced. Finally, convert moles of CO2 to grams using its molar mass.
How many moles of carbon are in 0.100 moles of carbon dioxide?
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation If 5.9 moles of carbon react how many moles of CS2 are produced?
The balanced chemical equation for the reaction is: C + 2SO2 → CS2 + 2O2. From the equation, 1 mole of carbon produces 1 mole of CS2. Therefore, if 5.9 moles of carbon react, 5.9 moles of CS2 are produced.
How many moles of carbon dioxide are produced when 10.0 moles of propane are burned in excess oxygen on gas grill?
30 moles
How many moles of oxygen atoms are there in 100.0 moles of carbon dioxide?
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
The number of moles of carbon dioxide produced when 0.136 moles of 1-pentanol react with excess oxygen in a combustion reaction?
0.678 - 0.682
How many grams of carbon dioxide are produced when 23.5 g of propanol react with excess oxygen in a combustion reaction?
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
A production of carbon dixode with a bioligcal method?
Carbon dioxide is an organic compound which consists of carbon and oxygen. It can be produced in biological method. When the carbohydrates are converted into starch then into glucose it reacts with the oxygen taken by respiration and forms 6 moles of water and 6 moles of carbon dioxide releasing 673 k cal of energy.
How many moles of oxygen atoms are present in one half mole of carbon dioxide molecules?
Since each mole of carbon dioxide molecules contains two moles of oxygen atoms, as indicated by the formula CO2 for carbon dioxide, half a mole of carbon dioxide will have one mole of oxygen atoms.
How many moles of carbon dioxide will be formed upon the complete reaction of 22.2 grams of carbon with excess oxygen gas?
Balanced equation. C + O2 -> CO2 22.2 grams carbon (1 mole C/12.01 grams)(1 mole CO2/1 mole C) = 1.85 moles carbon dioxide produced -------------------------------------------------
What is the mass ofCO2 if you have 85g of oxygen?
85g of oxygen = 85/16 moles of O atoms = 5.3125 moles There are 2 moles of oxygen atoms per mole of carbon dioxide, so we have 2.65625 moles of carbon dioxide. This is 2.65625 x 44 g = 116.875 g.
How many moles of carbon dioxide would be produced if 2.5 mole of Calcium carbonate is consumed?
1 mole of calcium carbonate produces 1 mole of carbon dioxide when it decomposes. Therefore, if 2.5 moles of calcium carbonate is consumed, 2.5 moles of carbon dioxide will be produced.
How many moles of carbon are there from the original sample of 11.0 grams of carbon dioxide and 4.50 grams of water with a combustion of 7.50 grams?
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
When methane is burned with oxygen the products are carbon dioxide and water If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen how many grams of carbon dioxide were pr?
To find the grams of carbon dioxide produced, start by calculating the moles of each reactant using their molar masses. Then determine the limiting reactant (the one that forms less product). In this case, oxygen is the limiting reactant. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass.
How many moles of oxygen will be produced from the complete combustion of 4 moles of propane?
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means that 5 moles of oxygen are required to completely combust 1 mole of propane. Therefore, 20 moles of oxygen would be produced from the complete combustion of 4 moles of propane.
