The equation for the formation of carbon dioxide from carbon and oxygen is C + O2 -> CO2 . Therefore, one mole of carbon dioxide can be formed from each mole of diatomic oxygen. To the justified number of significant digits, the gram molecular mass of diatomic oxygen is 32. Therefore 54/32 or 1.69 moles of carbon dioxide can be produced. (The last digit is smaller than the others to show that it may not be accurate within 1 digit.)
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
1.2 Moles
0.750 mol
First, write out your balanced equation. CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g) Then, since you know by Avogadro's Law, the volume is directly proportional to the number of moles. Since 3 moles of oxygen gas form one mole of carbon dioxide, you divide 4.50 x 102 mL, or 450. mL, and you get 150. mL of CO2 (g). Since 3 moles of oxygen produce 2 moles of sulfur dioxide, you take 450. mL and multiply it by (3/2) and get 300. mL of SO2 (g).
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
30 moles
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
0.678 - 0.682
11,2 moles carbon dioxide are obtained.
22 grams carbon dioxide (0.5 moles)
Carbon dioxide is an organic compound which consists of carbon and oxygen. It can be produced in biological method. When the carbohydrates are converted into starch then into glucose it reacts with the oxygen taken by respiration and forms 6 moles of water and 6 moles of carbon dioxide releasing 673 k cal of energy.
114,426 g carbon dioxide are produced.
Since each mole of carbon dioxide molecules contains two moles of oxygen atoms, as indicated by the formula CO2 for carbon dioxide, half a mole of carbon dioxide will have one mole of oxygen atoms.
The gram molecular mass of hexane is 86.18. Therefore, 25.0 g of hexane constitute 25.0/86.18 or 0.290 moles. Each mole of hexane contains six carbon atoms and therefore will produce six molecules of carbon dioxide by burning in an excess of oxygen. 6 X 0.290 = 1.74 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.00. Therefore, the mass of carbon dioxide produced will be 1.74 X 44.00 or 76.6 grams of carbon dioxide, to the justified number of significant digits.
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
85g of oxygen = 85/16 moles of O atoms = 5.3125 moles There are 2 moles of oxygen atoms per mole of carbon dioxide, so we have 2.65625 moles of carbon dioxide. This is 2.65625 x 44 g = 116.875 g.
1.2 Moles