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How many moles of krypton are there in 6.11 L of the gas at 802 atm and 31 degrees celsius?
Wiki User
∙ 12y ago
802 atmospheres? You sure? Anyway, the formula is the important thing.
Use the ideal gas equation/law.
pressure atm * volume Liters = moles * R * temperature Kelvin
PV = nRT
31 degrees Celsius = 304.15 Kelvin
(802 atm)(6.11 Liter) = n(0.08206 L*atm/mol*K)(304.15 K)
4900.22 = 24.959n
= 196 moles of Krypton
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Wiki User
∙ 12y ago
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