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The number of atoms in 0.40 mole of ANY element or compound is:
0.40 mol x 6.022x1023 atoms/mol = 2.4x1023 atoms.
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How many sulfur atoms are there in 3.1 mole of sulfur?
To find this, you simply multiply the number of moles by avogadro's number which is 6.22 X 10^23. 3.1 x 6.022x10^23 = 1.9 x 10^24 atoms of sulfur.
How many sulfur atoms are in 0.45 mol?
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
How many atoms are there in 72.0 g of sulfur?
72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur
How many moles of sulfur atoms are present in 3.00 moles of cs2?
6. 1 mole of CS2 contains 1 mole of carbon and 2 of sulfur.
How many moles of sulfur are found in 1.81 X 10 exp24 atoms of sulfur?
How many moles of sulphur in 1.81 X 1024 atoms of sulphur ? The answer is 3. The fact that we are talking about sulphur is immaterial. A mole is just another name for a gram molecular weight. The number of atoms in a gmw (mole) is given by Avogadro's Number, which is 6 X 1023 no matter what the element.
If you had a mole of sulfur atoms how many sulfur atomes would you have?
you would have 6.022 x 10^23 atoms (Avogadro's number)
Hown many atoms does 32 g of sulfur contain?
32g of Sulfur is a Mole of Sulfur and therefore contains Avogadro's number of atoms of Sulfur. Avogadro's number is 6.023 × 10 to the 23.
How many atoms in 1 mole molecule of sulfur?
Avagadro's number states that there are 6.022 x 10^23 atoms in 1 mole of any element.
What are the numbers of atoms in 0.250 mole sulfur?
The numbers of atoms in 0,250 mole sulfur is 1,50553521425.10e22.
How many sulfur atoms are there in 4.3 mole of sulfur?
2.6*10^24
If you have a mole of sulfur how many sulfur atoms do you have?
6.022x10^23 (Avogadro's constant)
How many atoms of Sulphur are found in 2 moles of S8?
2 mole S8 (8 mole sulfur/1 mole S8)(6.022 X 1023/1 mole sulfur) = 9.6 X 1024 atoms of sulfur --------------------------------------- Same as any atom ratio in a compound, moles of atoms over moles of the compound times Avogadro's number.
How many atoms does g of sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many sulfur atoms are there in 3.1 mole of sulfur?
To find this, you simply multiply the number of moles by avogadro's number which is 6.22 X 10^23. 3.1 x 6.022x10^23 = 1.9 x 10^24 atoms of sulfur.
How many atoms does 32 g sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many atoms 32 g of sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many sulfur atoms are in 0.45 mol?
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
