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You have to use dimentional analysis to answer this which i will try to do on a computer hah. you start off with your given with is fifty grams. You use the moalr mass for Amomonia which all you do is add each of the atoms molar mass together 14+1+1+1 I belive it is. you have to use avagadros number in this as well which is 6.02x10to the 23. you times 50 by avagadros number and divid that answer by 17 and you get your answer :)

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If you start with seventy grams of nitrogen and twenty grams of hydrogen how many grams of ammonia will be formed and how many grams of hydrogen are leftover?

To form ammonia (NH3) from nitrogen (N2) and hydrogen (H2), the balanced chemical equation is N2 + 3H2 → 2NH3. This means that for every mole of nitrogen, 3 moles of hydrogen are required. Given that nitrogen is limiting in this case, all 70 grams of nitrogen will react with 210 grams (3 times 70) of hydrogen to form 70 grams of ammonia. This reaction will consume all the hydrogen, leaving no grams of hydrogen leftover.


How many grams of kno3 can be dissolved at 50 degrees Celsius?

Approximately 200 grams of KNO3 can be dissolved in 100 ml of water at 50 degrees Celsius.


Jane has a mass of 50 kilograms Express her mass in grams and hectograms?

Jane's mass in grams: 50,000 grams Jane's mass in hectograms: 5 hectograms


How many grams of KCl to make 50 mL of 2.45 M KCl?

To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.


If A beaker contains 100 grams of 1.7 M NaCl and you transfer 50 grams what is the molarity of the solution in the beaker?

After transferring 50 grams of the 1.7 M NaCl solution to a new beaker, the final amount of NaCl in the original beaker will be 50 grams. To find the new molarity, you would first calculate the new moles of NaCl in the beaker, then divide by the total volume of the solution in liters. The molarity will be reduced in the original beaker due to the dilution from transferring a portion of the solution.