Type your answer here... The number of valence electrons in calcium is 20, because it's almost the same thing as it's atomic number.
Calcium has valence of 2, forming the calcium ion Ca2+. The phosphate ion, PO43- contains five valent phosphorus and divalent oxygen along with three extra electrons. Compounds do not have a valence, atoms have a valence.
Hydrogen has 1 valence electron, phosphorus has 5 valence electrons, and oxygen has 6 valence electrons. So, if you totaled all of the valence electrons in the ion HPO42- you'd get 1 + 5 + 6 X 4 + 2 = 32. However, you should realize that the term "valence electron" really only applies to individual atoms, not compounds. The only electrons one would concern themselves with in the HPO42- ion are the 2 that make it an ion.
Ca must lose 2 electrons to have a complete 3n shell, which has 8 valence electrons. The ion would have a charge of 2+: Ca^2+.
Argon. Calcium has the electron configuration 1s2 2s2 2p6 3s2 3p6 4s2, and when it loses its valence electrons (the outermost 4s2 electrons) it has a configuration identical to argon. If you don't know about sublevels, then disregard that. Calcium has a configuration of 2-8-8-2, and when it loses its 2 valence electrons, it has a configuration identical to argon in the ground state. Hope that cleared it up
the valence of CaCl2 is 2 because its not necessary that CaCl2 is always attached in hydrated form...... the basic thing which u study in your school classes that the outermost shell of both the element must be completed. so cacl2 has the valency of 2 because ca is electropositive. think it
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
Calcium has two valence electrons and needs to lose both to achieve a stable electron configuration, resulting in 8 valence electrons in the nearest noble gas configuration (argon). By losing these two electrons, calcium forms a cation with a charge of +2, resulting in a Ca²⁺ ion.
Depends on what you mean by number of electrons. Calcium has 20 electrons and oxygen has 8 electrons for a total of 28 electrons. But if you mean how many VALENCE electrons, then the calcium has 2 and the O has 6 for a total of 8 valence electrons.
A I ion, specifically iodide (I⁻), has a total of 8 valence electrons. In its neutral state, iodine has 7 valence electrons, but it gains one additional electron when it forms an ion, resulting in 8. Since each pair of valence electrons consists of 2 electrons, there are 4 pairs of valence electrons in an iodide ion.
Chlorine has 7 valence electrons. A chloride ion has 8.
Calcium (Ca) is an alkaline earth metal that typically loses two electrons to achieve a stable electron configuration when forming an ion. This results in the formation of a calcium cation (Ca²⁺). By losing these two valence electrons, calcium attains a noble gas configuration similar to argon.
Calcium has valence of 2, forming the calcium ion Ca2+. The phosphate ion, PO43- contains five valent phosphorus and divalent oxygen along with three extra electrons. Compounds do not have a valence, atoms have a valence.
Calcium loses its two valence electrons to become Ca 2+ ion.
Yes - but it is rare - usually has a + 2 charge
if you are asking about ICl4- ion then there are 28 valence electrons and 8 binding ones.total of 36 electrons
The most common ion of calcium (Ca) is the calcium ion (Ca²⁺), which forms when calcium loses two electrons. Calcium has an atomic number of 20, meaning it has 20 electrons in its neutral state. Therefore, the Ca²⁺ ion has 18 electrons.
Calcium typically loses 2 electrons to achieve a stable electron configuration, forming a Ca2+ ion. This results in a full outer energy level (valence shell), similar to the noble gas configuration of argon.