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538 J

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โˆ™ 12y ago
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โˆ™ 15y ago

The formula for specific heat is specific heat = energy/mass * change in temperature. Assuming the aluminum measure 5.5 *10 *10 cm, that gives a total mass of 1.48 kg, and a total energy requirement of 3108 Joules.

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โˆ™ 11y ago

Okay so we have the basic energy equation:

Q = m * Cp * dT

where Q = energy (Joules)

m = mass (grams)

Cp = heat capacity (J/g.C)

dT = change in temperature ( C)

here we have

Q = 216 J

Cp = 0.90 J/g.C

dT = 20C

so using the equation we find that:

12g

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โˆ™ 13y ago

dQ = dH = m*c_p*dT = 10*0.897*(10+273) = 2.54 kJ.

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โˆ™ 11y ago

420 cali hate e2020

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โˆ™ 14y ago

29,304 joules

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โˆ™ 6y ago

Approx 552.7 Joules.

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โˆ™ 13y ago

66 calories

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Q: How much energy is required to raise the temperature of 0.2 kg of aluminum from 15 and degC to 18 and degC (Refer to table of specific heat values.)?
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