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The formula for the quantity of heat Q = m s t

m- mass 0.375 kg s - specific heat capacity of water (4180 J/kg/K) t - the temperature change (25 deg C)

So, Q = 0.375 x 4180 x 25 = 39187.5 J

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14y ago
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10y ago

q(joules) = mass * specific heat * change in temperature

q = (5 grams H2O)(4.180 J/gC)(35o C - 25o C)

= 209 joules of heat

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Q: How much heat is needed to raise a 5 gram sample of liquid water from 25 Celsius to 35 Celsius?
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