-222.55 or -223
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It is 25 moles of Sodium Hydroxide (;
the molar mass of sodium hydroxide is 40g/mol mike
how much sodium hydroxide in grams must be added to seawater to precipitate 86.9mg of magnesium present?
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
1
It is 25 moles of Sodium Hydroxide (;
155.2 g
the molar mass of sodium hydroxide is 40g/mol mike
how much sodium hydroxide in grams must be added to seawater to precipitate 86.9mg of magnesium present?
0.2 mol
The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.
98g of phosphoric acid require 120g of sodium hydroxide to produce sodium phosphate so 150g phosphoric acid will require = 120/98x150= 183.67g sodium hydroxide.
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
98g
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