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simply use the formula DeltaTf=iKfm i= van't hoff number; Na3PO4 (sodium phosphate) van't hoff number is 4 m= molality moles of solute/kg of solvent in this case H2O Kf= the given number for Na3PO4 (sodium phosphate) is is ???*C/m just multiply those three things and that gives you the freezing point depression so we take the normal freezing point of water 0*C and we subtract the number we just calculated and that will give us the freezing point

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Q: How much sodium phosphate must be added to 1kg of water to lower the freezing point of water by 1.3 degree celsius?
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