First find moles hydrogen gas.
20 grams H2 (1 mole H2/2.016 grams)
= 9.921 moles H2
Now, the ideal gas equation.
PV = nRT
(1 atm)(volume L) = (9.921 moles H2)(0.08206 L*atm/mol*K)(298.15 K)
Volume of hydrogen gas = 243 Liters
----------------------------------------------------
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
The volume of hydrogen is 97, 86 L.
The balanced equation for the reaction between hydrogen gas (H2) and carbon disulfide (CS2) to produce methane (CH4) is: 4H2 + CS2 → 4H2S + CH4. This means that for every 4 moles of hydrogen gas, 1 mole of methane is produced. Since 1 mole of any gas at STP occupies 22.4 liters, you would need 5.6 liters of hydrogen gas to produce 2.5 liters of methane.
# This is a stoichiometry problem and requires a balanced chemical equation. N2 + 3 H2 ----> 2 NH3 If we assume that this reaction occurs at STP, then the number of moles of any gas at STP is equal to the volume (in litres) divided by 22.4 This will get you started.1500ml
Assuming it acts as an ideal gas then you use the equation PV=nRT where P=pressure (101.325 kPa at STP) V = volume 444 L (given) n = number of mols R = gas constant, 8.314472 L kPa K-1mol-1 T = temperature 273.15 K at STP I got 19.81 mols.
The molar volume of hydrogen gas at STP (Standard Temperature and Pressure) is 22.4 liters per mole.
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
For the reaction N₂ + 3H₂ → 2NH₃, the mole ratio of hydrogen gas to nitrogen gas is 3:1. Since 6 liters of hydrogen gas is used, you would need 2 liters of nitrogen gas at STP for this reaction according to the stoichiometry of the reaction.
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
Using the ideal gas law (PV = nRT), we can calculate the volume of gas at STP. First, we need to convert the number of molecules to moles by dividing by Avogadro's number. Then, we can use the volume of 1 mole of gas at STP, which is 22.4 liters. Calculate V = (5.4x10^24 / 6.022x10^23) * 22.4 to find the volume in liters.
The volume of hydrogen is 97, 86 L.
At STP (Standard Temperature and Pressure), the volume of 1 mole of any gas is 22.4 liters. Since hydrogen gas exists as H2 molecules, 67.2 liters of hydrogen gas at STP contains 3 moles of H2 molecules. Since each H2 molecule contains 2 hydrogen atoms, there are 6 moles of hydrogen atoms, which is equivalent to 6 x 6.022 x 10^23 atoms of hydrogen.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 15 liters of oxygen at STP would be equivalent to 15/22.4 = 0.67 moles.
The balanced equation for the reaction between hydrogen gas (H2) and carbon disulfide (CS2) to produce methane (CH4) is: 4H2 + CS2 → 4H2S + CH4. This means that for every 4 moles of hydrogen gas, 1 mole of methane is produced. Since 1 mole of any gas at STP occupies 22.4 liters, you would need 5.6 liters of hydrogen gas to produce 2.5 liters of methane.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
To find the number of hydrogen molecules, first calculate the number of moles in 31.8 L of H2 at STP using the ideal gas law. Then use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.