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Q = mcΔT

Q = (35.9 g) (4.184 J/(g*K)) (19.5 oC - 45.0 oC) (1 K / 1 oC)

Q = (35.9 g) (4.184 J/(g*K)) (-25.5 K)

Q = -3.83 * 103 J

Q = -3.83 kJ

The water has lost 3.83 kJ of energy, and this energy was supplied to the ice cube to melt it. A reasonable extension to the question would be to ask what was the mass of the ice cube added. This can be calculated with the molar enthalpy of fusion of ice: 6.01 kJ/mol

m = (3.83 kJ)/(6.01 kJ/mol) * (18.02 g / 1 mol)

m = 11.5 g

I think this also answers your other questions.

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15y ago
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14y ago

If an ice cube at 0 0 c melts to water by absorbing heat if 10.5 kcal of heat is required to melt ice how much energy must be lost to freeze water at 0 0 c to ice?

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Q: If an ice cube at 0 0 c melts to water by absorbing heat if 10.5 cal of heat is required to melt ice how much energy must be lost to freeze water at 0 0 c to ice?
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