Oversaturated, only around 35g of sodium chloride will dissolve at that 20C.
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
At 50 degrees on the solubility curve KClO3 should be saturated at 21g per 100g of water. Knowing this the one liter given to you in the question can be written as 1,000 ml or 1,000g of H2O since the density of water is 1g/ml. Set up an equation: 21g KCLO3/ 100g Water = x/ 1000g water x=210g Answer: 210g KClO3
At 313K, the solubility of potassium nitrate in water is approximately 62g/100g of water. To form a saturated solution in 50g of water, you would need roughly 31g of potassium nitrate.
To calculate the relative humidity, we need the actual vapor pressure (partial pressure) of water in the air and the saturated vapor pressure at the air temperature. At 20 degrees C, the saturated vapor pressure of water is around 2.34 kPa. By converting 3 grams of water to moles and calculating its partial pressure, we can find the relative humidity is approximately 46.2%.
saturatedsaturated
oversaturated
The solubility of NH4Cl in water at 50°C is approximately 74 grams per 100 grams of water. To make a saturated solution, you would need to dissolve 148 grams of NH4Cl in 200 grams of water.
The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.
At 60 degrees Celsius, the solubility of potassium chlorate (KClO₃) in water is approximately 7.2 grams per 100 grams of water. To create a saturated solution in 200 grams of water, you would need about 14.4 grams of potassium chlorate (7.2 g/100 g water x 200 g water = 14.4 g KClO₃). Thus, 14.4 grams of potassium chlorate would be required for saturation at this temperature.
The amount of Epsom salt in a saturated solution depends on factors such as temperature and pressure. At room temperature, approximately 115 grams of Epsom salt can dissolve in 100 mL of water to form a saturated solution.
To determine the total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution, you would need to know the solubility of 1-pentanol in water at a specific temperature. Once you have that information, you can calculate the total mass of 1-pentanol that will dissolve by adding the mass of the water to the mass of the 1-pentanol that can dissolve in it to form a saturated solution.
This is a solution of 10 g KCl/100 g water.
To determine the mass of NH4Cl needed to create a saturated solution in 200 grams of water at 50°C, we first need to consult the solubility data for NH4Cl at that temperature, which is approximately 37.2 grams per 100 grams of water. Thus, for 200 grams of water, the solubility would be about 74.4 grams of NH4Cl (37.2 g x 2). Therefore, you would need to dissolve approximately 74.4 grams of NH4Cl to achieve saturation at that temperature.
The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.
The solution become saturated ove 124,6 g potassium nitrate.
This is from the website linked to the left of this answer under Web Links:Solubility in water, g/100 ml at 20°C: 74.5Therefore, in 1 liter, 745.0 grams of CaCl2 will dissolve to make a saturated solution.
Saturated. This means it has dissolved the maximum amount of solute (in this case, HCl) at that temperature.