lead IV chlorate
Lead sulfate is not soluble in water.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
To test the percent purity of potassium chlorate, you can perform a titration with a known concentration of a reducing agent, such as iron(II) sulfate, and determine the amount of reducing agent needed to completely react with the potassium chlorate. From the titration results, you can calculate the purity of the potassium chlorate by comparing the actual amount of potassium chlorate in the sample to the theoretical amount that should be present based on the reaction stoichiometry.
The equation for the reaction between iron sulfate (FeSO4) and magnesium (Mg) is: FeSO4 + Mg -> MgSO4 + Fe. This is a single displacement reaction where magnesium replaces iron in the iron sulfate compound, forming magnesium sulfate and elemental iron.
yes you do. this is because the anyhdrate was white (crystals) and after adding water, it turned blue
Lead sulfate is not soluble in water.
Lead sulfate is not soluble in water.
When lead (IV) sulfate reacts with tin (II) chlorate, the lead (IV) cation (Pb^4+) will combine with the chlorate anion (ClO3^-) to form lead (IV) chlorate, Pb(ClO3)4. The tin (II) cation (Sn^2+) will combine with the sulfate anion (SO4^2-) to form tin (II) sulfate, SnSO4.
Yes, when iron comes into contact with copper sulfate, a chemical reaction occurs where the iron displaces the copper in the compound, forming iron sulfate and copper. This reaction is known as a displacement reaction.
The reaction between CuSO4 (copper(II) sulfate) and Fe (iron) is a single replacement reaction. The iron will displace the copper in the copper(II) sulfate solution, resulting in the formation of iron(II) sulfate and copper metal. The balanced chemical equation for this reaction is: Fe + CuSO4 -> FeSO4 + Cu. This reaction is also known as a displacement reaction, where a more reactive metal displaces a less reactive metal in a compound.
The reaction between mercuric sulfate and sulfuric acid forms mercuric hydrogen sulfate and sulfuric acid.
Fe+CuSO4^Cu+FeSO4
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
Yes, the reaction between zinc and copper sulfate is a single displacement reaction. In this reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper. The more reactive zinc replaces the less reactive copper in the compound.
When aluminum is added to copper sulfate, a displacement reaction occurs where aluminum displaces copper from the compound. This results in the formation of aluminum sulfate and copper metal. The reaction is exothermic and releases heat.
This compound is soluble in water.
The chemical equation for this reaction is MgCl2 + H2SO4 → MgSO4 + 2HCl. During the reaction, magnesium chloride and sulfuric acid react to form magnesium sulfate and hydrogen chloride gas. This is a double displacement reaction where ions in the reactants switch places to form the products.