Reaction between sodium and water produces hydrogen gas. This is not a precipitation, because the gas has a (much) lower density than the water and therefore evolves from it rather than precipitating.
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Sodium - Na. When silver nitrate is mixed with Sodium Hydroxide, Sodium Iodide, Sodium Phosphate a precipitate forms.
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.
Since it is a double displacement and the products of the reaction would be sodium nitrate and calcium carbonate, the precipitate would be calcium carbonate. This is because this reaction is a solubility based reaction, and sodium nitrate is a soluble compound (every metal is soluble in nitrate, and sodium dissolves in almost everything too). Whereas calcium carbonate is insoluble, and therefore will remain solid and form the precipitate.
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
Mixing sodium hydroxide and calcium nitrate will not form a precipitate. Instead, it will form solutions of sodium nitrate and calcium hydroxide.
an example of a precipitate is: silver nitrate + sodium chloride = silver chloride and sodium nitrate the precipitate is the silver chloride it forms a white powder
The precipitate formed when magnesium nitrate and sodium carbonate are mixed is magnesium carbonate. This is because sodium nitrate is soluble in water, leaving magnesium carbonate as the insoluble compound that precipitates out of the solution.
Answer: Cupric hydroxide (as bluish white precipitate) and sodium nitrate. Cu(NO3)2 + 2NaOH --> Cu(OH)2 + 2NaNO3
Silver bromide and sodium nitrate will react to form silver nitrate and sodium bromide as the products. The precipitate formed will be silver bromide, which is insoluble in water and will appear as a white solid in the reaction mixture.
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
When lead nitrate is mixed with sodium iodide, a solid precipitate of lead iodide is formed along with sodium nitrate. This reaction is a double displacement reaction where the cations of the two compounds switch partners to form the products. Lead iodide is a yellow precipitate that can be easily observed in the reaction mixture.
The reaction is:LNaCl + AgNO3 = AgCl + NaNO3The white precipitate is silver chloride.
Any precipitate is formed.
A precipitate is a solid which 'falls down' from the solution. Thus silver chloride is the precipitate.
Sodium - Na. When silver nitrate is mixed with Sodium Hydroxide, Sodium Iodide, Sodium Phosphate a precipitate forms.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.