Fe(NH4)3
but b sure to make the numbers subscript
Fe(NO3)3 + 3NH3 + 3H2O -> Fe(OH)3 + 3NH4+ + 3NO3 Net ionic equn= Fe+3(aq) + 3NH3(aq) + 3H2O -> Fe(OH)3(s) + 3NH4+(aq) Spectator ion= NO3-
(NH4)2S(aq) plus Pb(NO3)2(ag) ----> 2 NH4(NO3) (aq) and PbS (s)
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
3Mg + 2Fe(NO3)3 ----> 3Mg(NO3)2 + 2Fe
Iron (III) thiocyanate The nitrate ions will separate and form potassium nitrate as well. BE: Fe(NO3)3(aq) + 3K(SCN) -> Fe(SCN)3 + 3K(NO3)
Fe(NO3)2+ Na2S2O3-----> 2NaNO3+ S2+ 2FeO3
3AgNO3 + FeCl3 ---> 3AgCl + Fe(NO3)3
Yes.
It is ionic.
meep
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
3Mg + 2Fe(NO3)3 ----> 3Mg(NO3)2 + 2Fe
Zn2 + Fe3NO3 -> Zn3NO2 + Fe3
There is no reaction.
69
Electronegativity Fe = 1.83; O = 3.44 3.44 - 1.83 = 1.61 Since the electronegativity difference is 1.61 the bond is polar covalent 0 - 0.4 = Pure Covalent Bond 0.41 - 1.7 = Polar Covalent Bond 1.7 + = Ionic Bond
The chemical equation is:Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
The chemical equation is:3 AgNO3 + FeCl3 = 3 AgCl + Fe(NO3)33 Ag + 3 NO3- + Fe3+ + 3 Cl- = 3 AgCl(s) + 3 NO3- + Fe3+