4K + O2 --> 2K2O
The coefficient of oxygen is 1 but, 1 is understood and never written as a coefficient.
2K+Cl2------->2KCl
2KBr + Cl2 ----> 2KCl + Br2
The combination of potassium (K) and oxygen (O2) produces K2O (potassium oxide). The balanced equation is 2K + O2 ==> K2O. The answer provided previously is incorrect. The compound KO does not exist.
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
4K + O2 = 2K2O so the "coefficient" is 1
4KClO3= 3KClO4+KCl
give me balanced equation for potassium gold cyanide? give me balanced equation for potassium gold cyanide?
2K + Cl2 ---> 2KCl
2K+Cl2------->2KCl
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
KClO3
It is impossible to balance that equation.
2KClO3 --> 2KCl + 3O2
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
2KBr + Cl2 ----> 2KCl + Br2
The combination of potassium (K) and oxygen (O2) produces K2O (potassium oxide). The balanced equation is 2K + O2 ==> K2O. The answer provided previously is incorrect. The compound KO does not exist.