I think it's white.
The flame of potassium iodide is typically violet or purple in color.
When bleach is mixed with potassium iodide, it undergoes a redox reaction. The bleach oxidizes the iodide ions to produce iodine, which can be observed as a brown color. This reaction can be used to test for the presence of bleach in a solution.
They are not soluble, therefore they do not precipitate or form a color....a.k.a....no reaction...
When potassium iodide reacts with starch and hydrogen peroxide, it produces a brown color. This reaction is commonly used as a test for the presence of starch in a solution due to the formation of a blue-black complex called the "starch-iodine complex."
When ferric chloride (FeCl3) is added to a solution of potassium iodide (KI), it reacts to form iron(III) iodide (FeI3) and potassium chloride (KCl). The iron(III) iodide produced is a brownish-red color, indicating the presence of the Fe3+ ion. This reaction can be represented by the following chemical equation: 2FeCl3 + 6KI -> 2FeI3 + 6KCl
The flame of potassium iodide is typically violet or purple in color.
The endpoint color of sodium hypochlocrite and potassium iodide is not listed.
Chloroform is used in the assay of potassium iodide because it forms a complex with iodine liberated from potassium iodide in presence of acid, and this complex has a pink color that can be easily detected. This color change helps in monitoring the reaction and determining the concentration of potassium iodide in the sample.
When potassium iodide is oxidized, it forms iodine. Potassium iodide loses electrons hence it is oxidized. This reaction can be observed by the change in color of the solution from colorless to brown/yellow due to the formation of iodine.
Starch changes to a blue-black color in the presence of potassium iodide and sodium hypochlorite. This reaction is commonly used as a test for the presence of starch in a solution.
When bleach is mixed with potassium iodide, it undergoes a redox reaction. The bleach oxidizes the iodide ions to produce iodine, which can be observed as a brown color. This reaction can be used to test for the presence of bleach in a solution.
The reaction between potassium iodide and potassium bromide in the presence of methylene blue will result in the formation of elemental iodine (I2) which imparts a purple color to the solution. Initially, the reaction mixture will be colorless, but as iodine forms, the solution will turn purple.
They are not soluble, therefore they do not precipitate or form a color....a.k.a....no reaction...
When potassium iodide is added to a solution of bromine, a reaction occurs forming potassium bromide and iodine. The iodine produced in the reaction is responsible for the color change in the solution from orange to brown/black.
The reaction between potassium iodide and lead (II) nitrate forms lead iodide, which is a yellow pigment used in paint. Lead iodide provides a vibrant color and good coverage when used in paint formulations.
When potassium iodide reacts with starch and hydrogen peroxide, it produces a brown color. This reaction is commonly used as a test for the presence of starch in a solution due to the formation of a blue-black complex called the "starch-iodine complex."
When ferric chloride (FeCl3) is added to a solution of potassium iodide (KI), it reacts to form iron(III) iodide (FeI3) and potassium chloride (KCl). The iron(III) iodide produced is a brownish-red color, indicating the presence of the Fe3+ ion. This reaction can be represented by the following chemical equation: 2FeCl3 + 6KI -> 2FeI3 + 6KCl