HCO3- + H2O ---> H2CO3 + OH-
Bicarbonate is basic so it will accept the proton from the water molecule.
I think you mean H+ + HCO3- --> H2CO3
No, because it reacts with the acetic acid in vinegar. NaHCO3 + CH3COOH -> CO2 + CH3COONa +H2O or, in words, sodium bicarbonate plus acetic acid yields carbon dioxide plus sodium acetate plus water.
Silver iodide is highly insoluble in water, so you should expect no product.
Carbonic Acid - H2CO3
H2O + SO3 --> H2SO4 The product is sulfuric acid.
The equation is H2O + CO2 + CaCO3 --> Ca(HCO3)2
Any acid 1) will produce water plus carbon dioxide out of a (any) bicarbonate:H+ + HCO3- --> H2O + CO2Added:1) Except those weaker than carbonic acid H2CO3, eg. NH4+, H2S and HCN won't do this.
Sodium bicarbonate dissolves in water, that is all that will happen.
The chemical reaction for the decomposition of sodium bicarbonate is sodium hydrogen carbonate gives sodium carbonate plus water plus carbon dioxide. 2NaHCO3 = Na2CO3 + H2O + CO2 Remember that all the numbers except the initial 2 must be subscripts.
H2CO3 is carbonic acid and contains hydrogen and carbonate (2 hydrogen, 1 carbon and 3 oxygen).
I greatly doubt that aluminium bicarbonate exists. The bicarbonate ion requires a large, non-polarising cation for stability, and aluminium ions are small and highly polarising. There is even dispute whether aluminium carbonate exists.
I think you mean H+ + HCO3- --> H2CO3
Hydrochloric acid + Sodium Bicarbonate--------------->Sodium Chloride + Water + Carbon Dioxide
When ever a carbonate or bicarbonate reacts with water it evolves CO2 and H2O, in this case HCOOH (Formic acid) is a gas and NaHCO3 is a solid material so aqueous medium (Water) is required for reaction. NaHCO3 + HCOOH -------> HCOO- + Na+ + H2O + CO2..
No, because it reacts with the acetic acid in vinegar. NaHCO3 + CH3COOH -> CO2 + CH3COONa +H2O or, in words, sodium bicarbonate plus acetic acid yields carbon dioxide plus sodium acetate plus water.
the name for Na(HCO3) is sodium bicarbonate
NaHCO3 + H2O = H2CO3 +OH + Na