Silver iodide is highly insoluble in water, so you should expect no product.
H2O + SO3 --> H2SO4 The product is sulfuric acid.
Si02 plus h20 ---> h2Si03
HCO3- + H2O ---> H2CO3 + OH- Bicarbonate is basic so it will accept the proton from the water molecule.
CaCO3+2HCl----->CaCl2+H2O+CO2
No, the balanced equation is 6Ca + 3O2 ---> 6CaO. The product, calcium oxide, is CaO and not CaO2.
H2O + SO3 --> H2SO4 The product is sulfuric acid.
Si02 plus h20 ---> h2Si03
HCO3- + H2O ---> H2CO3 + OH- Bicarbonate is basic so it will accept the proton from the water molecule.
H20
No, it is a product. C6H12O6 + O2 + H20 = CO2 + H20 + ATP
baoh2
water [H20]
4
Silver iodide is not soluble in ammonia solution.
This is the iodhydric acid.
Nothing there won't be a reaction.
I think it is H20