Na2B4O7.10H2O (borax) + 2HCl ---> 2NaCl + 4H3BO3 + 5H2O
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
it is formed by mixing hydrochloric acid in sodium hydroxide. Naoh+Hcl=Nacl+H2o
1.4 moles - the HCl is the limiting ingredient
For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl
Balanced equation. H2 + Cl2 >> 2HCl 146 grams HCl (1mol/36.458g)(1mol Cl2/2mol HCl)(70.9g/11mol Cl2) = 72.9 grams
no
When HCl and NaOH react common salt (NaCl) is formed .This reaction is also called neutralization reaction .
There is no reaction between KF and HCl.
MgCl + H20
Salt and water are formed NaOH + HCl --> NaCl + H2O
When KOH reacts with HCl, these products are formed. This is a neutralization reaction. KOH is a base while HCl is an acid.
when the penny is reacted with HCl, there must be somesort of area where the copper on the outside of the penny is removed so that the HCl can react with the zinc inside because HCl does not react with copper. Once the HCl reacts with the Zn inside, it will dissapear and therefore become less dense then the ZnCl2 that is formed which causes the penny to float
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
Hydrogen Chloride gas --> HCl or Hydrochloric Acid --> HCl(aq)
When zinc granules are reacted with dilute HCl (hydrochloric acid), zinc chloride i.e. ZnCl2 is formed along with the evolution of hydrogen gas H2.
The easiest way to prepare the aldehyde is the reduction of acid chlorides, the by product is HCl. R-COCl + 2[H] = R-CHO + HCl
No. of mol of NaOH used = 30/1000 x 0.125 = 0.00375No. of mol of HCl used = 25/1000 x 0.15 = 0.00375No. of mol of HCl used = No. of mol of NaOH used.Hence, the resultant solution will be neutral. pH ~ 7.(NaCl formed is a neutral salt, does not undergo any form of salt hydrolysis)