If an aqueous solution of copper(II) sulfate is contacted with metallic iron, at the least the surface of the iron passes into solution and is replaced by a layer of metallic copper. This is an example of displacement by a metal higher in the electromotive series than the metal it displaces.
The iron will displace the copper as it is more reactive. here's the equation: iron + copper sulphate = iron sulphate +copper
The product of iron and copper (II) sulfate is iron (II) sulfate and copper. This reaction is a single displacement reaction where the more reactive metal (iron) displaces the less reactive metal (copper) from the compound.
Iron is more reactive than copper, allowing it to displace copper from copper sulfate solution through a single displacement reaction. This process forms iron sulfate and solid copper metal, as iron has a higher affinity for sulfate ions than copper does.
Yes, there is a fast reaction when iron is placed in copper sulfate solution. The iron reacts with the copper sulfate to form iron sulfate and copper metal. This results in a displacement reaction where the more reactive iron displaces the less reactive copper from the solution.
The formula for iron is Fe. The formula for copper sulfate is CuSO4. The chemical equation for the reaction is Fe (s) + CuSO4 (aq) --------- Cu (s) + FeSO4(aq) The iron is a more active metal than copper therefore it replaces the copper in the copper sulfate solution.
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
The word equation for the reaction between iron sulfate and copper is: iron sulfate + copper → copper sulfate + iron.
i don't know :P
When copper sulfate is added to iron, a chemical reaction takes place where the copper in the copper sulfate replaces the iron to form copper metal and iron sulfate. This reaction can be represented by the equation: CuSO4 + Fe → FeSO4 + Cu.
Iron is more reactive than copper, so when iron is added to copper sulfate solution, iron displaces copper in the reaction and forms iron sulfate. This process is known as a displacement reaction. This allows copper to be extracted from copper sulfate solution using iron.
The difference in temperature rise between zinc and iron with copper sulfate is due to their differing reactivities. Iron is more reactive than zinc, so it releases more energy when reacting with copper sulfate. This higher reactivity results in a greater increase in temperature during the reaction.
When an iron nail is placed in a copper sulfate solution, a single displacement reaction occurs. The iron will displace the copper in the solution, forming iron sulfate and depositing copper on the nail, causing it to turn a brownish color due to the presence of copper.
When iron is added to copper sulfate, a displacement reaction occurs where the iron displaces the copper in the compound to form iron sulfate and copper metal. This reaction results in a color change from blue (copper sulfate) to green (iron sulfate) as the copper ions are replaced by the iron ions.
When iron(III) reacts with copper sulfate, a displacement reaction occurs where iron displaces copper from copper sulfate. This results in iron(II) sulfate and copper being produced as products. The iron displaces copper because it is higher in the reactivity series.
Since iron is a more active metal than copper, the iron would replace the copper in the copper sulfate, forming iron sulfate, and releasing elemental copper. The copper will not shape itself into a copper vessel, so eventually, the iron sulfate would leak out of the iron vessel, and eventually, if there is enough copper sulfate, the iron vessel will cease to exist.
The iron will displace the copper as it is more reactive. here's the equation: iron + copper sulphate = iron sulphate +copper
The product of iron and copper (II) sulfate is iron (II) sulfate and copper. This reaction is a single displacement reaction where the more reactive metal (iron) displaces the less reactive metal (copper) from the compound.