iron + copper sulphate ''goes to'' iron sulphate + copper
If an aqueous solution of copper(II) sulfate is contacted with metallic iron, at the least the surface of the iron passes into solution and is replaced by a layer of metallic copper. This is an example of displacement by a metal higher in the electromotive series than the metal it displaces.
The iron will displace the copper as it is more reactive. here's the equation: iron + copper sulphate = iron sulphate +copper
The formula of green vitriol is FeSO4·7H2O, which represents iron(II) sulfate heptahydrate.
Copper sulfate has CuSO4 as its formula. Copper sulfate is also written copper (II) sulfate.
Copper(II) sulfate
The Copper(II) ion (I'm assuming) would oxidize the solid Iron metal (I'm assuming) to form Iron(II) and solid copper metal precipitate.
When iron(III) reacts with copper sulfate, a displacement reaction occurs where iron displaces copper from copper sulfate. This results in iron(II) sulfate and copper being produced as products. The iron displaces copper because it is higher in the reactivity series.
When iron (Fe) reacts with copper(II) sulfate (CuSO₄), a single displacement reaction occurs. In this reaction, iron displaces copper, resulting in the formation of iron(II) sulfate (FeSO₄) and elemental copper (Cu). The overall reaction can be represented as: [ \text{Fe} + \text{CuSO}_4 \rightarrow \text{FeSO}_4 + \text{Cu} ] Thus, the products formed are iron(II) sulfate and copper.
If an aqueous solution of copper(II) sulfate is contacted with metallic iron, at the least the surface of the iron passes into solution and is replaced by a layer of metallic copper. This is an example of displacement by a metal higher in the electromotive series than the metal it displaces.
Word equation: Iron + Copper (II) sulfate → Iron (II) sulfate + Copper Chemical equation: Fe + CuSO4 → FeSO4 + Cu
The iron will displace the copper as it is more reactive. here's the equation: iron + copper sulphate = iron sulphate +copper
Mercury, Iron or Nickel will not replace copper in a reaction between copper II sulfate and the metals because the metals are below copper in the reactivity level of the periodic table.
The anhydrous copper(II) sulfate is white, the pentahydrate is blue.Iron is gray.
The balanced chemical equation for the reaction between an iron nail (Fe) and copper sulfate (CuSO4) is: Fe + CuSO4 -> FeSO4 + Cu This reaction involves a single displacement reaction where iron displaces copper from copper sulfate to form iron(II) sulfate and copper metal.
The reaction between CuSO4 (copper(II) sulfate) and Fe (iron) is a single replacement reaction. The iron will displace the copper in the copper(II) sulfate solution, resulting in the formation of iron(II) sulfate and copper metal. The balanced chemical equation for this reaction is: Fe + CuSO4 -> FeSO4 + Cu. This reaction is also known as a displacement reaction, where a more reactive metal displaces a less reactive metal in a compound.
If an iron nail is placed in a copper(II) sulfate solution, the iron ions are exchanged with the copper ions, creating iron sulfate and copper (which precipitates out as copper metal). Fe + CuSO4 --> FeSO4 + Cu
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2