Ks = [Pb2+]*[I-]2 = 1.4*10-8 , at equilibrium, in saturated solution that is.
You can look it up in chemistry tables about solubility constants:Ks(PbI2) = 1.4*10-8 (mol3L-3)
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Produces yellow Lead(II) iodide and Sodium nitrate
The yellow product of reaction is lead (II) iodide, PbI2. It was used as the pigment in yellow paint, just as lead (II) oxide was the pigment in white paint. However, since these compounds were linked to lead poisoning, this procedure was discontinued. Currently, lead iodide is used as a detector for high energy photons, like x-rays or gamma rays, as the lead atom is very large.
The solubility product of Lead (II) sulphate , PbSO4 is very low and it is almost insoluble in water.
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
You can look it up in chemistry tables about solubility constants:Ks(PbI2) = 1.4*10-8 (mol3L-3)
Lead(II) iodide is yellow in colour
Lead (II) iodide Transition metals always need roman numerals to represent their charges.
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
Lead(II) iodide is yellow in colour
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
The name of compound Pbl2 is lead(II) iodide.
Produces yellow Lead(II) iodide and Sodium nitrate
Lead(II) iodide and Sodium nitrate
It produces Potassium nitrate and Lead iodide