Most likely copper.
The ion is Cu2+.
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
Ice is non-metallic. It is simply water (H2O) in the solid state and contains no elements that are metallic.
The Sulfates mineral group typically contains one or several metallic elements
Magnetite
Usually a metallic element will not react with water and so will not change pH. However, a highly reactive metal, such as sodium, potassium or calcium will react with water to form the corresponding metal hydroxide, and so forms a base.
Ammonium hydroxide
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
If you mean a basic solution that has a metal in its formula, it is usually just _ hydroxide. Example: Ca(OH)2 is a basic solution and its name is CALCIUM hydroxide (calcium is the metal). Mg(OH)2 -> Magnesium hydroxide etc.
A double replacement reaction takes place when aluminum sulfate reacts with ammonium hydroxide; the precipitate will be aluminum hydroxide (the ammonium sulfate will remain in solution, and we're assuming the reactants were already in aqueous solution.) Most metallic hydroxides are insoluble. The balanced equation for this reaction, showing the appropriate states of matter is:Al2(SO4)3(aq) + 6NH4OH(aq) --> 3(NH4)2SO4(aq) + 2Al(OH)3(s)
The pink precipitate is finely divided copper, reduced to its metallic form by displacement from copper sulfate by iron, which is higher in the electromotive series than copper. Iron sulfate remains in solution.