When Na2CO3 reacts with Nitric acid, The products at first are Sodium Hydrogen Carbonate and Sodium Nitrate...
HNO3 + Na2CO3 --> NaNO3 + NaHCO3
If again The leftover Sodium hydrogen carbonate is made to react with Nitric Acid, then the products will be:
HNO3 + NaHCO3 --> NaNo3 + H2O + CO2
The balanced reaction for N2H4 + H2O2 --> N2 + H2O is N2H4 + 2H2O2 --> N2 + 4H2O
The balanced chemical equation for the reaction of C2H6O (ethanol) with O2 (oxygen) to form CO2 (carbon dioxide) and H2O (water) is: C2H6O + 3O2 → 2CO2 + 3H2O.
3Fe + 4(H2O) ---> Fe3O4 + 4(H2) You really should learn this, its not that hard =D
Aluminum forms a +3 ion, and hydroxide's formula is OH-, so the formula for aluminum hydroxide would be: Al(OH)3
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
The balanced equation is: 4Al₄C₃ + 12H₂O → 4Al(OH)₃ + 3CH₄. This equation is balanced by ensuring that the number of each type of atom is the same on both sides of the equation.
Al(OH)3
Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation
Aluminium hydroxide - Al(OH)3
NaClO3 + 6 HCl = 3 Cl2 + 3 H2O + NaCl
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
Al(OH)3 is a base (Aluminum hyroxide)
The balanced equation for this reaction is Fe2O3 + 3 H2O = 2 Fe(OH)3.
This equation is:C2H5OH + 3 O2 = 2 CO2 + 3 H2O
The products are the new substances produced in the reaction, in this case carbon dioxide and water. Some people would say energy is a product too, there's no hard and fast rule about it.
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
The balanced chemical equation for the reaction NH3 + NO2 -> N2O + H2O is: 4 NH3 + 4 NO2 -> 3 N2O + 6 H2O