Oxygen on the anode and lead on the cathode. Since it's electrolysis, the reaction is not spontaneous.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
2I- + Pb2+ ? PbI2 (s)
Net Ionic: Pb2+(aq)+SO42-(aq) --> PbSO4(s) Molecular: Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)
Pure lead on the cathode and oxygen at the anode.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
To keep the kead nitrate in solution: otherwise it might precipitate lead.
The products will be lead hydroxide and sodium nitrate
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
2I- + Pb2+ ? PbI2 (s)
2I- + Pb2+ → PbI2 (s)
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
A thermally decomposition of the nitrate; the final products are lead oxide and nitrogen dioxide.
Net Ionic: Pb2+(aq)+SO42-(aq) --> PbSO4(s) Molecular: Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)
2NH4Cl (aq) + Pb(NO3)2 (aq) ----> 2NH4NO3 (aq) + PbCl2 (s)