Quantum numbers are a set of 4 imaginary numbers which explain the position and spin of electrons in an atom it can not explain an atom as a whole Iodine has 53 electrons so there are 53 sets of quantum numbers for Iodine.The above is correct. Assuming you meant to ask for the quantum numbers for the last electron added to Iodine, that would be n=5, l=1, m=0, s=1/2.
the four sets of quantum numbers are: 2, 0, 0, +1/2 2, 0, 0, -1/2 1, 0, 0, +1/2 1, 0, 0, -1/2
The quantum numbers used to describe the energy of the electrons of Fr are; 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2 4d10 5p6 4f14 5d10 6s2 6p6 7s1
I believe the answer is Ca3(PO4)2. All the numbers are subscripts.
(3,2,-1,-1/2)
What are the quantum numbers of Br?
from Max Planck's theory, quantum numbers are units of energy.
All four quantum numbers i.e principle ,azimuthal or subsidiary, magnetic and spin quantum numbers are required to specify a single atomic orbital.
http://en.wikipedia.org/wiki/Quantum_number
Principal quantum numbers (n).
The first three quantum numbers (principle, angular momentum, magnetic) are all whole numbers. The last quantum number (spin) is either ½ or -½.
The four quantum numbers, n, l, m1, and ms, are all solutions to Schrödinger's equation. These numbers are used to assign each electron in an atom an "address." They "uniquely characterize an electron and its state in an atom" ("Quantum Number").
How are electrons arranged in the quantum mechanical model of an atom
These are: principal quantum number (n), azimutal quantum number (ł), magnetic quantum number (m), spin quantum number (sd).
3s has a principle quantum number of n=3 5s has a principle quantum number of n=5
principal quantum number
You did not give any numbers