It carries a current at the set voltage of the line. Current is the actual electricity that flows along the line and is used up in your electric appliances whereas voltage is the difference between the energy being generated at the station and ground.
Answer
It carries both voltage and current. Voltage exists between each line conductor, and current flows through each line conductor.
By "kav", I'm assuming you mean "thousand-ampere-volts" ... usually represented as "KVA". Watts = (Volts) x (Amperes) x (power factor on the line) KW = KVA x (power factor on the line). The power factor on the line is the cosine of the phase difference between the voltage and current waveforms on the line.
Total voltage = the source. The voltage around the circuit is divided proportionally by each of the resistances in line. The current is = the source voltage divided by the sum of all the resistance.
The proper use of the term refers to the timing difference between voltages in a multi-phase power system. This makes more sense if you know that one complete AC cycle is divided up into 360 degrees, the same as a circle is. At 0 deg. the voltage is zero. At 90 deg. the voltage hits the positive peak. At 180 deg. the voltage falls back to zero. At 270 degrees the voltage falls to the negative peak. At 360 (same as zero) degrees, the voltage rises back up to zero, then the whole process repeats. In a 3-phase power system, each of the three hot conductors carry a voltage that is offset 120 degrees, or 1/3 of a cycle, from the next conductor. The voltage on each wire peaks at a slightly different time. However, in everyday use, the term phase has also come to mean which one of the three wires you want, as in "connect phase A to terminal 6", etc. It is even used in 240 volt (US) household power systems, where there are two different hot wires, even though it is technically not a multi-phase power system. So, if an electrician says phase, he most likely means one of the three hot wires in a 3-phase system.
The process by which a substance, such as iron or steel, becomes magnetized by a magnetic field. The induced magnetism is produced by the force of the field radiating from the poles of a magnet.AnswerThere is no such thing as a 'magnetic line of induction'. Induction is a process, by which a changing current induces (causes) a voltage into the same conductor or an adjacent conductor.A 'line' on the other hand, is imaginary and is simply a method of modelling a magnetic field in such a way that we can visualise its shape, rather in the same way that we use contour lines to show the shape of hills, etc.
The farthest time zone from your current location is the Line Islands Time Zone, which is 14 hours ahead of Coordinated Universal Time (UTC14).
For a line of given cross section and material, the power capacity will depend on the current carried, since resistance heating is proportional to (current)2 . For a given power, current is inversely proportional to voltage. Thus raising the voltage from 69 to 390 kv would reduce the current by a factor 69/390 = 0.177 , for the same power transmission, and reduce the heating losses by 0.1772 = 0.031. So you can see why high voltage for long distance lines is essential. Obviously the limiting current on a power line has to be set by economic and practical considerations, but if this is predetermined and set, the limiting power will be that which produces that limiting current, and power = voltage x current. The actual limiting curent will depend on the line cross section, material, and length. The power that a line of a certain voltage can carry is calculated by using the following formula: (2.55×(KV)2 /1000) MW.
Power = Current * Voltage * Power FactorAbove expression can further be explore as :1. For DC CircuitsPower = Current * Voltage2. For Single Phase AC CircuitPower = Current * Voltage * Power Factor3. For Three Phase AC CircuitPower = Line Current * Line Voltage * Power Factor
Carry electrical power over extremely long distanceswith minimal I2*R losses. The higher the line voltage the lower the current the line has to carry to transmit the power from source to load.
Power = Current * Voltage * Power FactorAbove expression can further be explore as :1. For DC CircuitsPower = Current * Voltage2. For Single Phase AC CircuitPower = Current * Voltage * Power Factor3. For Three Phase AC CircuitPower = Line Current * Line Voltage * Power Factor
Because power is power. If you maintain the same power, while increasing the voltage, you must decrease current. P=IE.
low current high voltage power dissipation in power line = I2R the resistance of the power line is hard to reduce, especially when it is a long transmission line. but reducing the current through the line reduces losses as the square, a dramatic savings. reducing voltage would have no effect and would dramatically increase losses due to increase in current to try to deliver same power.
The energy supplied by a power line is determined by its load, not by its voltage. For a given energy demand by its load, the higher the liine's voltage, the lower the resulting load current.
Voltage and current are actually inversely proportional to one another. The formula P=IV is what you need to look at here, where P is Power, V is voltage, and I is current. Rearranging the equation you will see that V = P/I. You can see that if you increase voltage, while holding power constant, current is reduced. Now, to your question. The losses on a transmission line are proportional to the current flowing on the line, so transmitting at high voltage (and hence low current) is beneficial as it reduces the amount of power that is lost due to resistance in the line itself.
In star the voltage from line to neutral is 1/sqrt(3) times the nominal voltage, while the load current equals the line current. In delta the voltage between lines is the nominal voltage, while the load current is 1/sqrt(3) times the line current (for a balanced load). So a delta load needs 3 times the resistance compared to a star load of the same power.
A power line carries electrical current from the power source to the load, delivering energy for use in homes and businesses. In contrast, a neutral line provides a return path for the current, completing the electrical circuit and ensuring safety by stabilizing the voltage. While the power line typically carries high voltage, the neutral line is grounded to prevent electrical shock and maintain a balanced system.
The RC circuit can reduce the phase shift between the voltage and current in the power line. The phase shift is caused by the inductance of the motor. The phase shift between the voltage and current in the power line causes problems due to the presence of so called imaginary current or power that does no work but must be supplied by the power source.
With a three-phase system the voltage quoted is the line-to-line voltage between any two live lines. To find the line-to-neutral voltage divide by 1.732 which is sqrt(3). The power supplied from each phase is the current times the line-to-neutral voltage (times the power factor if less than 1). To find the total power when the currents are equal, multiply by 3.