It reacts chemically and where safety goggles when you try it. WOW
One product will be AlCl3 Copper metal will be a product
Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).
When Na2CO3 reacts with Nitric acid, The products at first are Sodium Hydrogen Carbonate and Sodium Nitrate... HNO3 + Na2CO3 --> NaNO3 + NaHCO3 If again The leftover Sodium hydrogen carbonate is made to react with Nitric Acid, then the products will be: HNO3 + NaHCO3 --> NaNo3 + H2O + CO2
As Aluminium is more reactive than copper, it will replace the latter it its compound.2 Al + 3 CuSO4 ---> Al2(SO4)3 + 3 Cu
All metals more reactive than Zn: Al, Mg, Na, Ca, Ba, K, Li
One product will be AlCl3 Copper metal will be a product
CuCl2 and Al(s)
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2
the aluminum will dissolve. Generating lots of heat during the reaction
Al4C3 + 12 H2O → 4 Al(OH)3 + 3 CH4When aluminum carbide reacts with water, methane is formed.
Cu + HNO3 = CuNO3 + H2 or copper nitrate and hydrogen gasCu + 4 HNO3 --> Cu(NO3)2 + 2NO2 + 2H2OThe brown colored gas that comes of the reaction is NO2.
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) can be written as: 2Al(s) + 6H2O(l) → 2Al(OH)3(s) + 3H2(g).
Yes ! You add al four sides to get the result
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) to produce aluminum oxide (Al2O3) and hydrogen gas (H2) is: 4 Al + 3 H2O → 2 Al2O3 + 3 H2. From the balanced equation, we can see that 3 moles of water are needed for every 4 moles of aluminum reacting. Therefore, if 373 mol of aluminum is reacting, then (373 mol Al) x (3 mol H2O / 4 mol Al) = 279.75 mol of water would be produced.
Some metals react with alkalis; for example the reaction of aluminium with sodium hydroxide is:2 Al + 2 NaOH + 2 H2O = 2 NaAlO2 + 3 H2
Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).