It reacts chemically and where safety goggles when you try it. WOW
One product will be AlCl3 Copper metal will be a product
Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).
When Na2CO3 reacts with Nitric acid, The products at first are Sodium Hydrogen Carbonate and Sodium Nitrate... HNO3 + Na2CO3 --> NaNO3 + NaHCO3 If again The leftover Sodium hydrogen carbonate is made to react with Nitric Acid, then the products will be: HNO3 + NaHCO3 --> NaNo3 + H2O + CO2
As Aluminium is more reactive than copper, it will replace the latter it its compound.2 Al + 3 CuSO4 ---> Al2(SO4)3 + 3 Cu
All metals more reactive than Zn: Al, Mg, Na, Ca, Ba, K, Li
One product will be AlCl3 Copper metal will be a product
CuCl2 and Al(s)
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2
the aluminum will dissolve. Generating lots of heat during the reaction
Al4C3 + 12 H2O → 4 Al(OH)3 + 3 CH4When aluminum carbide reacts with water, methane is formed.
Cu + HNO3 = CuNO3 + H2 or copper nitrate and hydrogen gasCu + 4 HNO3 --> Cu(NO3)2 + 2NO2 + 2H2OThe brown colored gas that comes of the reaction is NO2.
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) can be written as: 2Al(s) + 6H2O(l) → 2Al(OH)3(s) + 3H2(g).
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) to produce aluminum oxide (Al2O3) and hydrogen gas (H2) is: 4 Al + 3 H2O → 2 Al2O3 + 3 H2. From the balanced equation, we can see that 3 moles of water are needed for every 4 moles of aluminum reacting. Therefore, if 373 mol of aluminum is reacting, then (373 mol Al) x (3 mol H2O / 4 mol Al) = 279.75 mol of water would be produced.
Yes ! You add al four sides to get the result
Some metals react with alkalis; for example the reaction of aluminium with sodium hydroxide is:2 Al + 2 NaOH + 2 H2O = 2 NaAlO2 + 3 H2
Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).