Nothing. Copper is lower than iron in the electromotive series and will not replace the iron in the iron nitrate solution.
We have just done a lab about single displacement reactions. Most students got a reaction in which the blue solution of copper (II) nitrate turned black/bronze color. Fe is above Cu in terms of reactivity series. Therefore, it will displace copper.
When Iron metal is dipped into a solution of copper sulfate a REDOX reaction occurs in which the Copper is reduced (gains electrons) and the iron is oxidised (loses electrons). When this happens, the iron metal becomes iron ions and the copper ions in the solution become copper metal. Cu2+(aq) + 2e- --> Cu(s) Fe(s) -->Fe2+(aq) + 2e- This occurs because the iron is a more active metal than copper, and as a general rule of thumb, a more reactive metal will displace a less reactive metal from solution. This principle underlies the action of the sacrificial electrode.
In this case, copper ions from the copper sulfate solution will react with the iron in the nail through a redox reaction. The iron will gradually dissolve into the solution, while copper ions will deposit on the surface of the nail, forming a layer of copper on the nail.
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
In certain reaction conditions, yes. Copper is more reactive than silver, so it should react with the nitrate molecule to form copper nitrate while precipitating the silver. *Are you thinking about separating silver from photographic fixer? Commonly a less expensive metal is used like iron (steel wool) to extract much of the silver.
The iron will replace the copper in the copper(II) nitrate solution, forming iron(II) nitrate and copper metal as products. The balanced chemical equation for the reaction is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu.
The word equation for the reaction between iron(III) nitrate and copper is: iron(III) nitrate + copper → copper(II) nitrate + iron.
The products of the reaction between iron and copper(II) nitrate are iron(II) nitrate and copper metal. Iron displaces copper in the compound because it is more reactive, leading to the formation of iron(II) nitrate and copper.
When iron is placed in copper sulfate solution, a chemical reaction occurs where the iron displaces the copper in the solution, forming iron sulfate and copper metal. This is known as a displacement reaction.
We have just done a lab about single displacement reactions. Most students got a reaction in which the blue solution of copper (II) nitrate turned black/bronze color. Fe is above Cu in terms of reactivity series. Therefore, it will displace copper.
the solution turns green and the nails develop a brown deposit which is copper. the iron displaces the copper in the copper sulphate solution. This is because iron is more reactive than copper.
The products of this single replacement reaction are iron(II) nitrate and copper. The iron displaces the copper in the reaction, resulting in the formation of iron(II) nitrate and elemental copper.
The reaction between iron and copper nitrate in a single replacement reaction would produce iron(II) nitrate and copper metal. The iron would replace the copper in the nitrate compound, resulting in the formation of iron(II) nitrate and copper metal as products.
The formula for iron reacting with copper(II) nitrate is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu. This is a single displacement reaction where iron displaces copper from copper nitrate to form iron(II) nitrate and copper metal.
When you put a copper bracelet in a solution of iron chloride, the iron in the iron chloride solution will displace the copper from the bracelet through a redox reaction, forming copper chloride solution and depositing iron on the bracelet's surface. This reaction demonstrates the principle of metal displacement reactions.
No. Iron is a more reactive metal than silver, so the iron will replace the silver in the silver nitrate solution, forming an iron nitrate solution and solid silver. Eventually, the iron container will be gone, its atoms having gone into the iron nitrate solution.
When Iron metal is dipped into a solution of copper sulfate a REDOX reaction occurs in which the Copper is reduced (gains electrons) and the iron is oxidised (loses electrons). When this happens, the iron metal becomes iron ions and the copper ions in the solution become copper metal. Cu2+(aq) + 2e- --> Cu(s) Fe(s) -->Fe2+(aq) + 2e- This occurs because the iron is a more active metal than copper, and as a general rule of thumb, a more reactive metal will displace a less reactive metal from solution. This principle underlies the action of the sacrificial electrode.