Sodium phosphate is obtained.
Na2HPO4, Na3PO4,NaH2PO4
Combine phosphoric acid and sodium hydroxide, very carefully, this will leave you with what you can utilise as sodium phosphate.
None! Trisodium phosphate is the end produce of neutralizing phosphoric acid with sodium hydroxide. So, no further reaction is possible.
Phosphoric Acid dissociates to give off 3H+ ions, meaning that one mole of Phosphoric acid reacts with three mols of sodium hydroxide. Using the equation n = c x v n = 0.1 x 0.05 =0.005 mols of OH ions in the solution therefore there are 0.005/3 = 0.00167 So the volume of phosphoric acid - v = n/c v = 0.00167/0.2 v = 0.00835 l = 8.4ml of Phosphoric Acid reacts completely with Sodium hydroxide
NaOH + H3PO4 --> Na3PO4 NaOH + H3PO4 -->
98g of phosphoric acid require 120g of sodium hydroxide to produce sodium phosphate so 150g phosphoric acid will require = 120/98x150= 183.67g sodium hydroxide.
Hydrochloric acid Sulfuric acid Phosphoric acid Sodium hydroxide Calcium hydroxide Potassium hydroxide
Yes, indeed!
Na2HPO4, Na3PO4,NaH2PO4
With a calculator. That is the easiest way.
Combine phosphoric acid and sodium hydroxide, very carefully, this will leave you with what you can utilise as sodium phosphate.
None! Trisodium phosphate is the end produce of neutralizing phosphoric acid with sodium hydroxide. So, no further reaction is possible.
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
Since Sodium Hydroxide is a base and hydrochloric acid is an acid, you will make water and sodium chloride.
Phosphoric Acid dissociates to give off 3H+ ions, meaning that one mole of Phosphoric acid reacts with three mols of sodium hydroxide. Using the equation n = c x v n = 0.1 x 0.05 =0.005 mols of OH ions in the solution therefore there are 0.005/3 = 0.00167 So the volume of phosphoric acid - v = n/c v = 0.00167/0.2 v = 0.00835 l = 8.4ml of Phosphoric Acid reacts completely with Sodium hydroxide
sodium lactate
NaOH + H3PO4 --> Na3PO4 NaOH + H3PO4 -->