The noble gas, krypton
1-Atomic size = decreases 2-Ioniztion energy = increases 3-Electronegativity = increases (except Argon) 4-Metallic character = decreases 5-Melting point = first increases then decreases
Ionization energy is referred to the amount of energy required to remove an electron from it's nucleus.The first ionization energy refers to the valence electron (the electron on the outer most shell)Blatantly, we can say that is requires less energy to remove valence electrons, rather than electrons in other orbitals, because it is farther away from the proton and therefore take less energy to remove that electron (ionization energy).The large discrepancy between the first and second ionization energies can be accounted for, by some of these factors:- such as shielding: basically the inner most electrons block some of the attractive forces from the nucleus (protons) and the valence electrons therefore have the most electrons blocking for them, because they are "in front" of all of the other electrons, on the outer most shell. Having this energy blocked means they are more free to move about.-Inverse square relationship between the first and Nth (n) shell: I won't write the entire equation but basically:the energy to be removed from the first shell is / by n^2, where n is the shell where the electron is removed from.Hence for the first (n=1) shellIE from 1st/ 1^2 = IE/1 = IE , this means that the energy to be removed from the first shell relative to itself is = which is true. This step is important.However, if we use the second shell (n=2), this is the second ionization energy.IE/2^2 = IE/4 , this means 4Xtimes LESS energy is needed to remove an electron from the second shell compared to the firstand then, if we use the third shell (n=3), which is the valence electron , also the FIRST Ionization energy.IE/3^2 = IE/9 , this means 9Xtimes LESS energy is needed to remove an electron from the third shell compared to the first.Conclusion: if we compare the first and second ionization energies, they are radically different from one another and there's a large discrepancy between the values due to the inverse square relationship between IE from the first energy level to the Nth level.
Period 4 and period 5 of the periodic table have the same number of elements. There are 18 elements in each period. While some elements in period 4 are calcium, iron, and zinc, elements in period 5 are tin, antimony, and iodine.
4 since it is in period 4 of the Periodic Table of Elements
Potassium belongs to group-1. It has one valence electron.
Carbon has the highest ionization energy in Group 4 of the periodic table. This is because as you move across a period from left to right, the ionization energy generally increases due to increase in effective nuclear charge. Among the elements in Group 4 (carbon, silicon, germanium, tin, lead), carbon has the highest ionization energy.
The element with the smallest first ionization energy is Francium, as it is located in Group 1 of the periodic table and has the largest atomic size. Among the elements listed, lithium (Li) would have the smallest first ionization energy as it is closer to the upper right of the periodic table compared to sodium (Na), potassium (K), and rubidium (Rb).
Ionization energy generally increases from left to right across period 4 due to increasing nuclear charge. Electrons are added to the same energy level as you move across the period, resulting in a stronger attraction between the electrons and the nucleus, making it harder to remove an electron.
The energy required to remove an electron from an atom (ionization energy) generally increases from left to right across period 4. This is due to the increasing nuclear charge and decreasing atomic size, which result in stronger attraction between the nucleus and the outer electron being removed. As you move from potassium to iron, the ionization energy generally increases with some variations due to subshell electron configurations.
Imagine that one electron has already been removed from an atom, the energy used to accomplish this is the 1st ionization energy. Now more energy is needed to remove a 2nd electron. That is the 2nd ionization energy.
Atomic radius decreases across a row (increasing positive charge in the nucleus causes electrons in the same energy level to "shrink" into the nucleus due to electrostatic attraction). This means that potassium has the largest atomic radius in period 4.
Iron is in period 4 of the periodic table because it has 4 energy levels or electron shells surrounding its nucleus. In periods, elements are ordered based on the number of electron shells they have. Iron has 4 energy levels, placing it in period 4 of the periodic table.
There are 4 electronic shells in period 4 while there are 5 shells in period 5.Elements of period 4 are smaller in size as compared to elements of period 5.Example of period 4 element is potassium and period 5 element is tin.
IONIZATION:-The splitting up of a substance in to a negative and positive ions in it's aqueous solution or in fused form is known as ionization.DEGREE OF IONIZATION:-The extent to which an electrolysis can ionize in water is called it's degree of ionization.Degree of ionization of CH3COOH = 4/1000
gain 4 electrons:- Because the energy released (electron affinity) for the addition of four electrons is too high, Lose 4 electrons:- energy required to lose electrons (the sum of the first 4 ionization energies) is too high
Potassium is in the 4th period and has 4 energy levels.
I am not sure if it is possible to get a second electron out from hydrogen, but I know how to get the IP of an electron with quantum state n=2. The equation for the ionization energy in quantum state n is En=E1/(n^2). En is the ionization in quantum state n, E1 is the ground state ionization energy, which is 13.6eV and n is the quantum state. So, if n=2, then the potential is reduced by 1/4, and the IP would be 3.40 eV.