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2Al(NO3)3 + 3Na2S = Al2S3 + 6NaNO3
Is the balanced equation.
Notice
There are 2 x Al on both sides
There 2 x 3 = 6 nitrates on both sides
There are 3 x 2 = 6 sodium on both sides
There 3 sulphur on both sides.
NNB
The Al cation has a '3+' charge, so to make it neutral molecules it needs 3 nitrate anions each with a '1- 'charge ( 3 x 1- = 3-) The charges balance.
The sodium cation has a '1+' charge . There being 3 x 2 = 6 Na gives a 6+ charge . To balance the sulfide anion has a '2-' charge, so 3 are needed ( 3 x 2- = 6- charge. hence the charges balance.
The 6 x sodium nitrate each has a '1+' and a '1-' charge so the charges balance.
Finally Al2S3 is 2 x 3+ = 6+ charge on the aluminium cation , this is balanced by 3 x 2- = 6- charge on the sulphur anion.
Hope that helps!!!!
If the specified reagents are in aqueous solution when reacted, the actual reaction occurs according to the balanced equation 2 Al+3 (aq) + 3 S-2 (aq) -> Al2S3 (s).
If a full compound equation is preferred, that would be 2 Al(NO3)3 + 3Na2S -> 6 NaNO3 + Al2S3.
Potassium and nitrate don't react, stay unchanged as hydrated ions in solution, called spectator ions.
Only sulfate and barium ions react by precipitating to solid.
(SO42-)aq + (Ba2+)aq --> (BaSO4)s
The balanced equation for the reaction between aluminum nitrate and sodium sulfide is:
2Al(NO3)3 + 3Na2S → 6NaNO3 + 2Al2S3
Barium Nitrate is Ba(NO3)2, and Aluminum Sulfate is Al2(SO4)3. The net equation for their reaction is 3 Ba(NO3)2 + Al2(SO4)3 --> 3 BaSO4 + 2 Al(NO3)2
Ammonium sulfate reacts with barium nitrate to form ammonium nitrate and barium sulfate.
(NH4)2SO4 + Ba(NO3)2 ==> NH4NO3 + BaSO4
It is a double replacement reaction.
This equation is Al2(SO4)3 (aq) + 3 BaCl2 (aq) -> 2 AlCl3 (aq) + 3 BaSO4) (s).
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What is a balanced equation for mercury II nitrate and sodium sulfide?
The balanced chemical equation for the reaction between mercury(II) nitrate and sodium sulfide is: Hg(NO3)2 + Na2S -> HgS + 2NaNO3
How many grams of aluminum hydroxide are obtained from 15.7 of aluminum sulfide?
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
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The balanced equation for the reaction between aluminum sulfide and water is: Al2S3 + 6H2O → 2Al(OH)3 + 3H2S. This reaction forms aluminum hydroxide and dihydrogen sulfide gas.
How many grams of aluminum hydroxide are obtained from 17.2 grams of aluminum sulfide?
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
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The net ionic equation for the reaction of silver nitrate (AgNO3) and ammonium sulfide (NH4)2S is: Ag+ + S2- -> Ag2S. This equation represents the formation of silver sulfide precipitate as a result of the reaction.
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The balanced chemical equation for the reaction between aluminum sulfide and iron II nitrate is: 2 Al2S3 + 3 Fe(NO3)2 -> 2 Al(NO3)3 + 3 FeS
What is a balanced equation for mercury II nitrate and sodium sulfide?
The balanced chemical equation for the reaction between mercury(II) nitrate and sodium sulfide is: Hg(NO3)2 + Na2S -> HgS + 2NaNO3
How many grams of aluminum hydroxide are obtained from 15.7 of aluminum sulfide?
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The balanced equation for this reaction is: 2 Na2S + 2 AgNO3 → Ag2S + 2 NaNO3
What is the balanced equation of aluminum sulfide water -- aluminum hydroxide dihydrogen sulfide gas?
The balanced equation for the reaction between aluminum sulfide and water is: Al2S3 + 6H2O → 2Al(OH)3 + 3H2S. This reaction forms aluminum hydroxide and dihydrogen sulfide gas.
Balanced chemical equations mercury sulfide plus ammonium nitrate?
A balanced equation has equal numbers of each type of atom on each side of the equation.Balanced chemical equations mercury sulfide plus ammonium nitrate is as follows :Hg2(SO4) + 2[(NH4)(NO3)] ----> 2[Hg(NO3)] + {[(NH4)2] (SO4)}
What is the balanced equation for sodium sulfide plus copper II nitrate to form sodium nitrate plus copper II sulfide?
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What does ammonium sulfide and iron 2 nitrate yield?
Ammonium sulfide reacts with iron(II) nitrate to form iron(II) sulfide and ammonium nitrate. The balanced chemical equation for this reaction is: (NH4)2S + Fe(NO3)2 → FeS + 2NH4NO3. Iron(II) sulfide is a black solid precipitate that forms in this reaction.
How many grams of aluminum hydroxide are obtained from 17.2 grams of aluminum sulfide?
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
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What is balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution.?
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