What is a balanced equation for Aluminum nitrate and sodium sulfide?

Answer 1

2Al(NO3)3 + 3Na2S = Al2S3 + 6NaNO3

Is the balanced equation.

Notice

There are 2 x Al on both sides

There 2 x 3 = 6 nitrates on both sides

There are 3 x 2 = 6 sodium on both sides

There 3 sulphur on both sides.

NNB

The Al cation has a '3+' charge, so to make it neutral molecules it needs 3 nitrate anions each with a '1- 'charge ( 3 x 1- = 3-) The charges balance.

The sodium cation has a '1+' charge . There being 3 x 2 = 6 Na gives a 6+ charge . To balance the sulfide anion has a '2-' charge, so 3 are needed ( 3 x 2- = 6- charge. hence the charges balance.

The 6 x sodium nitrate each has a '1+' and a '1-' charge so the charges balance.

Finally Al2S3 is 2 x 3+ = 6+ charge on the aluminium cation , this is balanced by 3 x 2- = 6- charge on the sulphur anion.

Hope that helps!!!!

Answer 2

If the specified reagents are in aqueous solution when reacted, the actual reaction occurs according to the balanced equation 2 Al+3 (aq) + 3 S-2 (aq) -> Al2S3 (s).

If a full compound equation is preferred, that would be 2 Al(NO3)3 + 3Na2S -> 6 NaNO3 + Al2S3.

Answer 3

Potassium and nitrate don't react, stay unchanged as hydrated ions in solution, called spectator ions.

Only sulfate and barium ions react by precipitating to solid.

(SO42-)aq + (Ba2+)aq --> (BaSO4)s

Answer 4

Al2(SO4)3 + 3 Ba(NO3)2 = 3 BaSO4 + 2 Al(NO3)3

Answer 5

Barium Nitrate is Ba(NO3)2, and Aluminum Sulfate is Al2(SO4)3. The net equation for their reaction is 3 Ba(NO3)2 + Al2(SO4)3 --> 3 BaSO4 + 2 Al(NO3)2

Answer 6

(NH4)2 SO4 + Ba(NO3)2 ---> 2NH4NO3 + BaSO4

Answer 7

Ammonium sulfate reacts with barium nitrate to form ammonium nitrate and barium sulfate.

(NH4)2SO4 + Ba(NO3)2 ==> NH4NO3 + BaSO4

It is a double replacement reaction.

Answer 8

This equation is Al2(SO4)3 (aq) + 3 BaCl2 (aq) -> 2 AlCl3 (aq) + 3 BaSO4) (s).

Answer 9

CuSO4 + Ba(NO3)2 --> BaSO4 + Cu(NO3)2

Answer 10

Ba 2+ + SO4 2- ===> BaSO4