H2S + FeCl2 --> FeS + 2 HCl
The iron sulfide will precipitate out, making this reaction nonreversible.
When hydrogen sulfide gas is bubbled through a solution of iron III chloride, it forms iron III sulfide as a solid precipitate. This reaction is represented by the chemical equation: FeCl3 + 3H2S -> Fe2S3 + 6HCl.
As a stronger oxidizing agent than Iodine, Chlorine oxidizes the Iodide ions to Elementary Iodine, while itself gets reduced to Chloride. The equation for this reaction is:Cl2 + 2 I- ----> 2 Cl- + I2
The reaction is a redox reaction where chlorine is reduced to chloride ions and iodide ions are oxidized to elemental iodine. Overall, it is a displacement reaction where chlorine displaces iodine from sodium iodide to form sodium chloride and elemental iodine.
Chlorine is a more reactive halogen than bromine, therefore, when chlorine gas is bubbled through a calcium bromide solution, the chlorine will take the place of the bromine. This is called an anionic single replacement (displacement) reaction. Cl2(g) + CaBr2(aq) --> Br2(l) + CaCl2(aq)
Chlorine is a stronger oxidizer than elemental Bromine. So, when yellowish chlorine gas is bubbled through the Bromide solution, a red colour is formed which is Bromine. Chlorine oxidizes Bromide ions to elemental Bromine while itself is reduced to Chloride ions. So, the total reaction is: Cl2 + Br- ----> Br2 + Cl-
When hydrogen sulfide gas is bubbled through a solution of iron III chloride, it forms iron III sulfide as a solid precipitate. This reaction is represented by the chemical equation: FeCl3 + 3H2S -> Fe2S3 + 6HCl.
When hydrogen gas is bubbled through hydrochloric acid in the presence of magnesium ribbon, the reaction produces magnesium chloride salt solution and hydrogen gas. This is a single displacement reaction where magnesium displaces hydrogen in hydrochloric acid to form the products.
When carbon dioxide is bubbled into a hydrogen carbonate indicator, the indicator solution will turn yellow. This is due to the formation of carbonic acid, which is a weak acid. The carbon dioxide reacts with water in the indicator solution to form carbonic acid, causing the color change.
As a stronger oxidizing agent than Iodine, Chlorine oxidizes the Iodide ions to Elementary Iodine, while itself gets reduced to Chloride. The equation for this reaction is:Cl2 + 2 I- ----> 2 Cl- + I2
Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.
The hydrogen carbonate solution would turn cloudy white due to the formation of calcium carbonate precipitate as a result of the reaction between hydrogen carbonate and calcium ions in the snails' shells.
Hydrogen.
If ammonia is bubbled through an acid, an ammonium salt and hence ion of that acid is formed. Ammonia bubbled through HCl would form ammonium chloride.
The reaction is a redox reaction where chlorine is reduced to chloride ions and iodide ions are oxidized to elemental iodine. Overall, it is a displacement reaction where chlorine displaces iodine from sodium iodide to form sodium chloride and elemental iodine.
Hydrogen Peroxide H2O2 is chemically unstable, and exposure to a catalyst will cause it to convert into Oxygen Gas and Water. The bubbles are Oxygen Gas. The equation that describes this change is 2H2O2 ---> O2 + 2H2O Even light, heat or age can trigger this decomposition reaction.
HCl (g)+ KCN (aq) --> HCN (aq) + KCl(aq) HCl will not dissociate due to it being a gas, but since KCN is group 1A, it will split into K+ and Cl- ions, and HCN is a weak acid, so it will not dissociate either, and KCl will dissociate due to it also being Group 1A, so it will make up K+ and Cl- ions, so the net ionic equation will be HCl(g)+ K+(aq) + CN-(aq) --> HCN(aq) + K+(aq) + Cl-(aq)
The reaction is a redox reaction where chlorine gas oxidizes iodide ions to form iodine molecules, while the chlorine is reduced to chloride ions. This is a single displacement reaction where chlorine displaces iodine in sodium iodide to form sodium chloride.